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Real Analysis




                    Notes          where we have taken y = g(x). Hence h is continuous at a which proves the theorem.
                                   Let us now study the following example:


                                          Example: Examine for continuity the following functions:
                                   (i)  The polynomial function f R ® R defined by
                                                                                 n
                                                           f(x) = a, + a x + a x  +... + a x .
                                                                         2
                                                                    1   2       x
                                   (ii)  The rational function f: R ® R defined as
                                                                f(x)
                                                           f(x) =   ,  "  x for which q(x)  0.
                                                                q(x)
                                   Solution:
                                   (i)  It is obvious that the function f(x) = x, x  R, is continuous on the whole of the real line. It
                                                                            3
                                       follows from theorem 3 that the functions x , x ,...., are all continuous. The fact that constant
                                                                         Z
                                       functions are continuous, we get that any polynomial f(x) in x, i.e., the function f defined
                                       by
                                                                         2
                                                                                 n
                                                           f(x) = a, + a x+ a x  +... + a  x ,
                                                                    1   2      n
                                       is continuous on R.
                                   (ii)  It follows from theorem 3(v) that a rational function f, defined by,
                                                                p(x)   a +  a x +  +  a x n
                                                           f(x) =    =   0  1      n
                                                                q(x)  b +  b x +  +  b x  m
                                                                                  m
                                                                       0
                                                                           1
                                       is continuous at every point a  R for which q(a)  0.
                                   11.3 Non-continuous Functions

                                   You have seen that a function may or may not be continuous at a point of the domain of the
                                   function. Let us now examine why a function fails to be continuous.
                                   A function f: S ® R fails to be continuous on its domain S if it is not continuous at a particular
                                   point of S. This means that there exists a point a  S such that, either

                                   (i)  lim f(x) does not exist, or
                                         -
                                        x a
                                   (ii)  lim f(x) exists but is not equal to f(a).
                                        x a
                                         -
                                   But you know that a function f is continuous at a point a if and only if
                                                          f(a+) = f(a–) = f(a).
                                   Thus, if f is not continuous at a, then one of the following will happen:
                                   (i)  either f(a+) or f(a–) does not exist (this includes the case when both f(a+) and f(a–) do not
                                       exist).

                                   (ii)  both f(a+) and f(a–) exist but f(a+)  f(a–).
                                   (iii)  both f(a+) and f(a–) exist and f(a+) = f(a–) but they are not equal to f(a).
                                   If a function f: S ® R is discontinuous for each b  S, then we say that totally discontinuous an S.
                                   Functions which are totally discontinuous are often encountered but by no means rare. We give
                                   an example.





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