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Complex Analysis and Differential Geometry




                    Notes          a tangent vector. Note that covariant and contravariant indices have different transformation
                                   laws, cf. (1) and (2).
                                                          3
                                   Proposition 1. Let  X : U    be a parametric surface, and let    X   be a reparametrization
                                                                                     X 
                                                                                          
                                                                                          j X ,
                                                                                   i
                                   of X. Then  T  X  T X.               X, and Z   z X   z j    then:
                                                                          
                                                      Furthermore, if  Z T
                                                 u   u                u     i
                                                                i
                                                               z   z j u  i j  ,                                     ...(1)
                                                                     u 
                                   where  d    u / u .  i     j 
                                   Proof. By the chain rule, we have:

                                                                    u i
                                                                
                                                               X     X .                                        ...(2)
                                                                       i
                                                                 j
                                                                    u   j
                                          
                                                                                              
                                   Thus  T X  T  (u)   X,   and  since we  can interchange  the  roles of  X and  X,   we conclude  that
                                         u 
                                                              j 
                                     
                                                             
                                   T X   T  (u)   X.  Substituting (2) in  z X ,  we find:
                                                               j
                                    u 
                                                                    i
                                                                   z X   z j u  i j X ,
                                                                   
                                                                     i
                                                                              i
                                                                         du 
                                   and (1) follows.
                                                                                          3
                                                                                           ,
                                   Definition  4.  A  vector  field  along a  parametric surface  X :U     is  a  smooth  mapping
                                           .   A vector field Y is tangent to X if Y (u)  T X for all u  U. A vector field Y is normal
                                   Y : U   3 2                              u
                                   to X if Y(u)  T X for all u  U.
                                               u
                                          Example: The vector fields X  and X  are tangent to the surface. The vector field X  × X 2
                                                                      2
                                                                                                          1
                                                                1
                                   is normal to the surface.
                                   We call the unit vector field
                                                                        X  X
                                                                    N   1   2
                                                                        X  X 2
                                                                         1
                                   the unit normal. Note that the triple (X , X , N), although not necessarily orthonormal, is positively
                                                                   2
                                                                1
                                   oriented. In particular, we can see that the choice of an orientation on X, e.g., X   X , fixes a unit
                                                                                                     2
                                                                                                1
                                   normal, and vice-versa, the choice of a unit normal fixes the orientation. Here we chose to use
                                   the orientation inherited from the orientation u   u  on U.
                                                                             2
                                                                         1
                                                                   2
                                   Definition 5. We call the map  N : U    the Gauss map.
                                   The Gauss map is invariant under orientation-preserving reparametrization.
                                   Proposition 2. Let  X : U    be a parametric surface, and let  N : U    be its Gauss map. Let
                                                                                            2
                                                         3
                                   
                                                                                                       
                                   X   X   be an orientation-preserving reparametrization of X. Then the Gauss map of  X is N  .
                                                                                                            
                                        
                                   2  We often visualize Y(u) as being attached at X(u), i.e. belonging to the tangent space of   at X(u); cf.
                                                                                                      3
                                     see footnote 1.
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