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Unit 14: Rings




          We define ‘+’ and ‘.’ in Z + iZ to be the usual addition and multiplication of complex numbers.  Notes
          Thus, foram + in and s + it in Z + iZ,
          (m + in) + (s + it) = (m + s) + i(n + t), and
          (m + in) . (s + it) = (p – nt) + i(mt + ns).
          Verify that Z + iZ is a ring under this addition and multiplication. (This ring is called the ring of
          Gaussian integers, after the mathematician Carl Friedrich Gauss.)
          Solution: Check that (Z + iZ, +) is a subgroup of (C, I–). Thus, the axioms RI-R4 are satisfied. You
          can also check that
          ((a + ib) . (c + id)) . (m + in) = (a + ib) . ((c + id) . (m + in))

            a + ib, c + id, m + in  Z + iZ.
          This shows that R5 is also satisfied.
          Finally, you can check that the right distributive law holds, i.e.,
          ((a + ib) + (c + id)) . (m + in) = (a + ib) . (m + in) + (c + id) . (m + in) for any a + ib, c + id, m +
          in  Z + iZ.
          Similarly, you can check that the left distributive law holds. Thus, (Z + iZ, + , .) is a ring. The
          operations that we consider in it are not the usual addition and multiplication.


                Example: Let X be a non-empty set, (XI ) be the collection of all subsets of X and A
          denote the symmetric difference operation. Show that ((X), A, n) is a ring.
          Solution: For any two subsets A and B of X,
          A  B = (A\B)  (B\A)

          It is clear that ( (X), A) is an abelian group. You also know that  is associative. Now let us see
          if  distributes over A.
          Let A, B, C E  (X). Then
           A  (B  C) = A  [(B\C)  (C\B)]
                    = [A  (B\C)][A  (C\ B)], since n distributes over U.

                    = [(A  B)\(A  C)][(A  C)\(A  B)], since  distributes over complementation.
                    = (A  B) A (A  C).
          So, the left distributive law holds.
            Also, (B  C)  A = A  (B  C), since  is commutative.
                          = (A  B) P (A  C)
                          = (B  A) A ( C  A).
          Therefore, the right distributive law holds also.
          Therefore, (  (X), A, ) is a ring.
          So’ far you have seen examples of rings in which both the operations defined on the ring have
          been commutative. This is not so in the next example.


                Example: Consider the set
                   a    11  a 12                   
          M (R) =   a  a     a, a , a , and a; are real numbers 
                              12
                                 21
            2
                      21  22                       

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