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Abstract Algebra




                    Notes          Now, given any f(x)  F[x], such that deg f(x) > 0, we will show that there is a field monomorphism
                                   from F into F[x]/d(x)>. This will show that F[x)/<f(x)> contains an isomorphic copy of F; and
                                   hence, we can say, that it contains F. So, let us define 0 : F  F[x]/d(x)>: (a) = a + <f(x)>.
                                   Then  (a+b) =  (a) +  (b), and

                                   (ab) = (a) (b).
                                   Thus,  is a ring homomorphism.
                                   What is Ker  ?
                                   Ker      = {a  F] a + <f(x)> = <f(x)>}

                                            = {a  F | a  <f(x)>}
                                            = {a  F | f(x) | a}
                                            = {0}, since deg f > 0 and deg a  0.
                                   Thus,  is 1-1, and hence an inclusion.

                                   Hence, F is embedded in F[x]/<f(x)>.
                                   Thus, if f(x) is irreducible in F[x], then F[x]/<f(x)> is a field extension of F.
                                   Well, we have looked at field extensions of any field F. Now let us look at certain fields, one of
                                   which F will be an extension of.

                                   24.2.1 Prime  Fields

                                   Let us consider any field F. Can we say anything about what its subfields look like? Yes, we can
                                   say something about one of its subfields. Let us prove this very startling and useful fact.
                                   Theorem 6: Every field contains a subfield isomorphic to Q or to Z , for some prime number p.
                                                                                        p
                                   Proof: Let F be a field. Define a function f : Z  F : f(n) = n.1 = 1 + 1 + .... + 1 (n times).
                                   f is a ring homomorphism and Ker f = pZ, where p is the characteristic of F.
                                   You know that char F = 0 or char F = p, a prime. So let us look at these two cases separately.

                                   Case 1 (char F = 0): In this case f is one-one.  Z = f(Z). Thus, f(Z) is an integral domain contained
                                   in the field F. Since F is a field, it will also contain the field of quotients of f(Z). This will be
                                   isomorphic’ to the field of quotients of Z, i.e., Q. Thus, F has a subfield which is isomorphic to Q.

                                   Case 2 (char F = p, for some prime p):
                                   Since p is a prime number, Z/pZ is a field.
                                   Also, by applying the Fundamental Theorem of Homomorphism to f, we get Z/pZ  f(Z). Thus,
                                   f(Z) is isomorphic to Z  and is contained in F. Hence, F has a subfield isomorphic to Z .
                                                     p
                                                                                                        p
                                   Let us Theorem 6 slightly. What it says is that:
                                   Let F be a field.
                                   (i)  If char F = 0, then F has a subfield isomorphic to Q.

                                   (ii)  If char F = p, then P has a subfield isomorphic to Z.
                                   Because of this property of Q arid Zp (where p is a prime number) we call these fields prime
                                   fields.







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