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Abstract Algebra                                              Sachin Kaushal, Lovely Professional University




                    Notes                          Unit 7: Homomorphism Theorem




                                     CONTENTS
                                     Objectives

                                     Introduction
                                     7.1  Fundamental Theorem of Homomorphism
                                     7.2  Automorphisms
                                     7.3  Summary
                                     7.4  Keywords

                                     7.5  Review Questions
                                     7.6  Further Readings



                                   Objectives


                                   After studying this unit, you will be able to:
                                       Discuss fundamental theorem of homomorphism
                                   
                                       Explain the concept of automorphism
                                   
                                   Introduction

                                   After understanding the concept of isomorphisms. Let us prove some result about the relationship
                                   between homomorphisms and quotient groups. The first result is the Fundamental Theorem of
                                   Homomorphism for groups. It is called ‘fundamental’ because a lot of group theory depends
                                   upon this result. This result is also called the first isomorphism theorem.

                                   7.1 Fundamental Theorem of Homomorphism

                                   Theorem 1 (Fundamental Theorem of Homomorphism): Let G  and G  be two groups and f : G 1
                                                                                           2
                                                                                     1
                                    G  be a group homomorphism. Then
                                      2
                                   G /Ker f  Im f.
                                    1
                                   In particular, if f is onto, then G /Ker f  G . 2
                                                            1
                                   Proof: Let Ker f = H. Note that H    G . Let us define the function
                                                                 1
                                    : G /H  Im f :  (Hx) = f(x).
                                       1
                                   At  first glance it seems  that the definition of  depends on  the coset  representative. But we
                                   will show that if x, y  G  such that Hx = Hy, then (Hx) = (Hy). This will prove that  is a
                                                       1
                                   well-defined function.
                                   Now, Hx = Hy  xy   H = Ker f  f(xy ) = e , the identity of G .
                                                   -1
                                                                    -1
                                                                                       2
                                                                        2
                                    f(x)[f(y)]  = e  f(x) = f(y).
                                            -1
                                               2
                                    (Hx) = (HY).

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