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Unit 29: Estimation of Parameters: Criteria for Estimates



            Comparing (1) and (2), we get                                                         Notes


                                ´
                            1.96 1600      æ 1.96 1600 ö  2
                                                ´
                        300 =          or  n = ç     ÷  =  109.3
                                n          è   300   ø
            Since this value is greater than 109, therefore, the size of the sample should be 110.
            29.3.2 Confidence Interval for Population Standard Deviation

                   1         2
            Let  S =  å (X -  X )  be the sample standard deviation of a random sample of size n drawn
                         i
                   n
            from a normal population with standard deviation s. It can be shown that the sampling distribution
                                                                                
            of S is approximately normal, for large values of n, with mean s and standard error   . Thus,
                                                                                2n
                 -
                S 
            z =       can be taken as a standard normal variate.
                / 2n
                   Example 11: A random sample of 50 observations gave a value of its standard deviation
            equal to 24.5. Construct a 95% confidence interval for population standard deviation  .
            Solution.

                                                                 
                                                            ( )
            It is given that S = 24.5 and n = 50 (large). We know that  . .S E S =  . Since s is not known, we
                                                                 2n
                                                               S    24.5
                                                          ( )
            use its estimate based on sample. Thus, we can write  . .S E S =  =  =  2.45 .
                                                               2n    100
            Hence 95% confidence interval for s is given by
            24.5 – 1.96 ´  2.45    24.5 + 1.96 ´  2.45  or  19.7    29.3




               Note    More examples on confidence intervals are given later with the questions on
              test of significance.


            29.4 Summary


                Let X be a random variable with probability density function (or probability mass function)
                 f(X ;  ,  , ....  ), where  ,  , ....   are k parameters of the population.
                     1  2    k       1  2   k
                 Given a  random sample X , X , ...... X  from this  population, we may  be interested in
                                       1  2     n
                 estimating one or more of the k parameters  ,  , ......  . In order to be specific, let X be a
                                                     1  2    k
                 normal variate so that its probability density function can be written as N(X :  , ). We
                 may be interested in estimating m or s or both  on the basis of random sample obtained
                 from this population.
                 It should be noted here that there can be several estimators of a parameter, e.g., we can
                 have any of the sample mean, median, mode, geometric mean, harmonic mean, etc., as an







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