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Unit 20: Cyclic Decomposition and the Rational Form




                                                                                                Notes
          Apply Step 2  with   1 ,....,  k  replaced by   1 ,.....,  k  and with   k .
          Conclusion: p  divides each p  with i < k.
                     k           i
          Step 4: The number r and the polynomials p , ... , p  are uniquely determined by the conditions
                                              1    r
          of Theorem 1.
          Suppose that in addition to the vectors   1 ,....,  r  in Theorem  1 we   have non-zero  vectors
            ,....,  r  with respective T-annihilators  g  ,....,g  such that
           1                                1    r
                             T
                  V  W 0  Z ( ; ) ... Z ( ; )                                     ...(11)
                                         T
                            i
                                       i
                 g  divides g  ,  k = 2, ..... , s.
                  k        k – 1
          We shall show that r = s and p  = g  for each i.
                                  i  i
          It is very easy to see that p  = g . The polynomial g  is determined from (11) as the T-conductor of
                               1  1               1
          V into W . Let S(V; W ) be the collection of polynomials f such that f  is in W  for each   in V, i.e.,
                 0         0                                          0
          polynomials f such that the range of f(T) is contained in W . Then S(V; W ) is a non-zero ideal in
                                                         0          0
          the polynomial algebra. The polynomial g  is the monic generator of that ideal, for this reason.
                                            1
          Each   in V has the form
                        f    ... f
                     0   1 1    s s
          and so
                            s
                  g   g       g f  .
                   1   1  0    1 i  i
                            1
          Since each g  divides g , we have g  = 0 for all i and g  = g   is in W . Thus g  is in S(V; W ). Since
                    i      1         1 i            1   1 0     0     1         0
          g is the monic polynomial of least degree which sends   into W  we see that g  is the monic
           1                                             1     0           1
          polynomial of least degree in the ideal S(V; W ). By the same argument, p  is the generator of
                                                0                     1
          that ideal, so p  = g .
                      1  1
          If f is a polynomial and W is a subspace of V, we shall employ the shorthand fW for the set of all
          vectors f  with  in W. We have left to the exercises the proofs of the following three facts.
                             T
                         (
                    T
          1.    f Z ( ; ) Z f  ; ).
          2.   If V V 1  ... V  where each V  is invariant under T, then  fV  fV 1  ...  fV k .
                             ,
                            k
                                         i
          3.   If   and   have the same T-annihilator, then  f  and f  have the same T-annihilator and
               (therefore)
                                                     Z
                                                          T
                                             T
                                     dim ( f  ; ) dim ( f  ; ).
                                        Z
          Now, we proceed by induction to show that r = s and p  = g  for i = 2, ...., r. The argument consists
                                                      i  i
          of counting dimensions in the right way. We shall give the proof that if r  2 the p  = g , and from
                                                                          2   2
          that the induction should be clear. Suppose that r  2. Then
                                                           V
                                               Z
                                    dim W 0  dim (  1 ; T ) dim .
          Since we  know that  p  =  g , we know that  Z( ; T) and  Z( ; T)  have the same dimension.
                            1   1                 1         1
          Therefore,
                                               Z
                                    dim W   dim ( ; T ) dim .
                                                           V
                                         0        1

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