Page 284 - DMTH502_LINEAR_ALGEBRA
P. 284

Linear Algebra




                    Notes
                                          Example 1: If V is an n-dimensional inner product space, then each ordered orthonormal
                                   basis   = { , …,   } determines an isomorphism of V onto F  with the standard inner product.
                                                                                   n
                                            1    n
                                   The isomorphism is simply
                                                            T (x   + … + x  ) = (x , …, x ).
                                                               1  1     n  n   1    n
                                   There is the superficially different isomorphism which   determines of V onto the space F n×1
                                   with (X|Y) = Y*X as inner product. The isomorphism is
                                                                          [ ]
                                                                            
                                   i.e., the transformation sending   into its coordinate matrix in the ordered basis  .  For any
                                   ordered basis  , this is a vector space isomorphism; however, it is an isomorphism of the two
                                   inner product spaces if and only if  is orthonormal.


                                          Example 2:  Here is a slightly less superficial isomorphism. Let  W be the space of all
                                                                                  t
                                   3 × 3 matrices A over R which are skew-symmetric, i.e.,  A  = –A. We equip W with the inner
                                                 1          1
                                                       t
                                   product (A|B) =   tr (AB ), the    being put in as a matter of convenience. Let V be the space R 3
                                                 2          2
                                   with the standard inner product. Let T be the linear transformation from V into W defined by
                                                                   0    x  x
                                                                         3  2
                                                      T (x , x , x ) =   x  0  x
                                                         1  2  3    3        1
                                                                   x 2  x 1  0
                                   Then T maps V onto W, and putting

                                                  0    x   x         0   y   y
                                                        3   2             3   2
                                             A =   x   0   x  , B =   y  0   y
                                                   3        1         3       1
                                                  x 2  x 1  0        y 2  y  1  0
                                   we have
                                                              t
                                                         tr (AB ) = x y  + x y  + x y  + x y  + x y
                                                                  3 3  2 2  3 3  2 2  1 1
                                                               = 2 (x y  + x y  + x y ).
                                                                    1 1  2 2  3 3
                                   Thus ( | ) = (T |T ) and T is a vector space isomorphism. Note that T carries the standard basis
                                   (  ,   ,   ) onto the orthonormal basis consisting of the three matrices
                                    1  2  3
                                                         0 0   0      0 0  1    0   1 0
                                                         0 0   1 ,    0 0 0 ,   1   0 0 .
                                                         0  1  0      1 0 0     0   0 0


                                          Example 3: It is not always particularly convenient to describe an isomorphism in terms
                                   of orthonormal bases. For example, suppose G = P*P where P is an invertible n × n matrix with
                                   complex entries. Let V be the space of complex n × 1 matrices, with the inner product [X|Y] =
                                   Y*GX.
                                   Let W be the same vector space, with the standard inner product (X|Y) = Y*X. We know that V
                                   and W are isomorphic inner product spaces. It would seem that the most convenient way to
                                   describe an isomorphism between V and W is the following: Let T be the linear transformation
                                   from V into W defined by T(X) = PX. Then
                                                        (TX|TY) = (PX|PY)




          278                               LOVELY PROFESSIONAL UNIVERSITY
   279   280   281   282   283   284   285   286   287   288   289