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P. 344

Linear Algebra




                    Notes          Thus a bilinear form  f is skew-symmetric if and only if its matrix  A is equal to –A  in some
                                                                                                       t
                                   ordered basis.
                                   When f is skew-symmetric, the matrix of f in any ordered basis will have all its diagonal entries
                                   0. This just corresponds to the observation that f( ,  ) = 0 for every   in V, since f( ,  ) = –f( ,  ).
                                   Let us suppose f is a non-zero skew-symmetric bilinear form on V. Since f   0, there are vectors
                                    ,   in V such that f( ,  )   0. Multiplying   by a suitable scalar, we may assume that f( ,  ) = 1.
                                   Let   be any vector in the subspace spanned by   and  , say   = c  + d . Then
                                                          f( ,  ) = f(c  + d ,  ) = df( ,  ) = –d

                                                          f( ,  ) = f(c  + d ,  ) = cf( ,  ) = c
                                   and so
                                                               = f( ,  )  – f( ,  )                        ...(1)
                                   In particular, note that   and   are necessarily linearly independent; for, if   = 0, then f( ,  ) =
                                   f( ,  ) = 0.
                                   Let W be the two-dimensional subspace spanned by   and  . Let W  be the set of all vectors   in
                                   V such that f( ,  ) = f( ,  ) = 0, that is, the set of all   such that f( ,  ) = 0 for every   in the subspace
                                   W. We claim that V = W   W . For, let   be any vector in V, and
                                                               = f( ,  )  – f( ,  )

                                                               =   –
                                   Then   is in W, and   is in W , for
                                                          f( ,  ) = f(  – f( ,  )  + f( ,  ) ,  )
                                                               = f( ,  ) + f( ,  )f( ,  )

                                                               = 0
                                   and similarly f( ,  ) = 0. Thus every   in V is of the form   =   +  , with   in W and   in W . From
                                   (1) it is clear that W   W  = {0}, and so V = W   W .

                                   Now the restriction of f to W  is a skew-symmetric bilinear form on W . This restriction may be
                                   the zero form. If it is not, there are vectors  ' and  ' in W  such that f( ',  ') = 1. If we let W' be the
                                   two-dimensional subspace spanned by  ' and  ', then we shall have
                                                             V = W   W'   W
                                                                           0
                                   where W  is the set of all vectors   in W  such that f( ',  ) = f( ',  ) = 0. If the restriction of f to W
                                          0                                                                   0
                                   is not the zero form, we may select vectors  ",  " in W  such that f( ",  ") = 1, and continue.
                                                                              0
                                   In the finite-dimensional case it should be clear that we obtain a finite sequence of pairs  of
                                   vectors,

                                                              ( ,  ), ( ,  ), ... , ( ,  )
                                                                1  1  2  2      k  k
                                   with the following properties:
                                   (a)  f( ,  ) = 1, j = 1, ... , k.
                                          j  j
                                   (b)  f( ,  ) = f( ,  ) = f[ ,  ) = 0, i   j.
                                          i  j   i  j   i  j
                                   (c)  If W  is the two-dimensional subspace spanned by   and  , then
                                           j                                     j    j
                                                             V = W    ...   W    W
                                                                   1       k   0
                                   where every vector in W  is 'orthogonal' to all  , and  , and the restriction of f to W  is the zero
                                                      0                  j    j                       0
                                   form.


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