Page 87 - DMTH502_LINEAR_ALGEBRA
P. 87

Unit 4: Co-ordinates




                                                                                                Notes
                                  x
          (b)  Let  g x  1,g x  cos ,g x  sin . Find an invertible 3×3 matrix P such that
                                            x
                   1       2         3
                    3
               g     P f
                j     ij i      for  j  1,2,3
                   i  1
                              ,
          Solution: Let  f x f x f x be a dependent set then we can find real  , ,c c c  not all of them
                         ,
                      1   2    3                                     1  2  3
          zero so that
                  c f x  c f x  c f x  0
                  1 1    2 2    3 3
          or      c 1 .1 c e ix  c e  ix  0                                        ...(1)
                       2
                            3
          Taking real part we have
                                                                                   ...(2)
                  c 1  c  2  cosx c 3  cosx  0
          Taking imaginary part we have
                                                                                   ...(3)
                  c  c  0
                  2   3
          From (2) we have  c 1  0,c 2  c  3  0 for arbitrary x,

          From (3) we have c 2  c  3
          So we get  c 1  c 2  c 3 .

                                                                   ,
                                                                ,
          which contradicts the statement that all c’s are not zero. So the set  f f f  is an independent set.
                                                                1
                                                                    3
                                                                  2
                     ,
                  ,
                                          ,
                                     ,
          So find  g g g  in terms of  f x f x f x we see that
                      3
                  1
                    2
                                            3
                                  1
                                       2
                  g x   f x  1
                   1    1
                              f x  f x
                  g x   cosx  2     3
                   2
                                  2
                             f x   f x
                  g x   sinx  2    3
                   3
                                 2i
                   g x    1  0    0    f x
                    1                   1
          Thus     g x    0 1/2  1/2   f x                                         ...(4)
                    2
                                        2
                   g x    0 1/2i  1/2i  f x
                    3                   3
                     1  0    0
          Thus   P   0 1/2 1/2                                                     ...(5)
                     0  i /2 /2
                            i
                        2i  i
          Also   Let  P       0                                                    ...(6)
                        4  2
          So P is invertible 3 × 3 matrix given by (5).

                                           LOVELY PROFESSIONAL UNIVERSITY                                   81
   82   83   84   85   86   87   88   89   90   91   92