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Topology




                    Notes
                                          Example 2:  Each interval and each ray in the real line in both connected and locally
                                   connected. The subspace [–1, 0)  (0, 1] of   is not connected, but it is locally connected.

                                   12.2.2 Locally Connected Subset

                                   Let (X, T) be a topological space and let (Y, T ) be a sub-space of (X, T)
                                                                      y
                                   The subset Y X is said to be locally connected if (Y, T ) is a locally connected space.
                                                                               y
                                   12.2.3 Theorems and Solved Examples

                                   Theorem 7: Every discrete space is locally connected.
                                   Solution: Let x be an arbitrary point  of a discrete space X. We know that  every subset of a
                                   discrete space is open and that every singleton set is connected. Hence {x} is a connected open
                                   nhd. of x. Also every open nhd. of x must contain {x}.
                                   Hence X is locally connected.


                                          Example 3: Give two examples of locally connected space which are not connected.
                                                                        Or

                                   Is locally connected space always connected? Justify.
                                   Solution:
                                   1.  Let X be a discrete space containing more than one point.
                                       Let x X. Then {x} is an open connected set and is obtained in every open set containing x.
                                       So, X is locally connected at each point of X. Also, every singleton subset of X is a non-empty
                                       proper subset of X which is both open and closed. So X is disconnected.
                                   2.  Consider the usually topological space (R, U)
                                       Let A R, which is the union of two disjoint open intervals.
                                       Then A is not a interval and therefore it is not connected.
                                       To show that A is locally connected.

                                       Let x be an arbitrary point of A and G  be a set open in A such that x G . Then there exists
                                                                     x                          x
                                       an open interval I  such that x  I  G . But I  being an interval, it is connected in R and
                                                      x            x   x    x
                                       therefore in A.
                                       Thus every open nhd. of x in A contains a connected open nhd. of x in A.
                                       Hence A is locally connected.

                                          Example 4: Give example of a space which is connected but not locally connected.

                                   Solution: Consider the subspace A B of the Euclidean Plane R , where
                                                                                     2
                                            A = {(0, y) : –1 y 1}
                                                              1     
                                   and      B =   (x,y) : y   sin    ,0 x  
                                                                      1
                                                                  
                                                              x     
                                   The A B = and each point of A is a limit point of  B and so A and B are not separated.
                                   Consequently, A B is connected.




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