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Unit 1: Topological Spaces
Notes
Note In every topological space, X and are open as well as closed.
1.3.2 Door Space
A topological space (X, T) is said to be a door space if every subset of X is either T-open or
T-closed.
Example 10: Let X = {1, 2, 3) and T = {, {1, 2}, {2, 3}, {2}, X}
Then, T-closed sets are X, {3}, {1}, {1, 3}, .
This shows that every subset of X is either T-open or T-closed.
1.3.3 Closure of a Set
Let (X, T) be a topological space and A is a subset of X, then the closure of A is denoted by A or
Cl (A) is the intersection of all closed sets containing A or all closed superset of A.
Example 11: If T = {, {a}, {a, b}, {a, c, d}, {a, b, c}, {a, b, c, d}, X} be a topology on X = {a, b,
c, d, e} then find the closure of the sets {a}, {b}
Solution: Closed subset of X are
, {a}, {a, b}, {a, c, d}, (a, b, e}, {a, b, c, d}, X = X, {b, c, d, e}, {c, d, e}, {b, e}, {c, d}, {e},
then { a } = X
{ b } = X {b, c, d, e} {b, e} = {b, e}
Theorem 3: A is closed iff A = A
Proof: Let us suppose that A is closed
A A (by definition of closure)
Now also A A (A is common in all supersets of A)
A = A
Conversely, let us suppose that A = A
Since we know that A is closed. (by definition of closure of A)
A = A is closed
A is closed
1.3.4 Properties of Closure of Sets
Theorem 4: Let (X, T) be a topological space and let A, B be any two subsets of X. Then
(i) = , X = X;
(ii) A A
(iii) A B A B
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