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Unit 16: The Countability Axioms




          Proof: Let (Y,  ) be a sub-space of a topological space (X, T) which is second countable so that  Notes
          there exists a countable base  for the topology T.
          If we show that (Y,  ) is second countable, the result will follow

                             is countable   ~ N
                                          is expressible as
                                            = {B  : N N}
                                               n
          Write

          (i)  Evidently   ~ N under the map Y B  n.
                        1                     n
                  is countable.
                   1
          (ii)    is a family of all  –open sets.
                1
               For                                    B   B  T,
                                   n        n
                                 B T  Y B  
                                               n
          (iii)  any y  G B  Y 
                                r      1
               s.t. y Y B  G.
                          r
          For proving this let G 

          s.t.   y  G, then H  T s.t. G = H Y.
                 y G y H Y y  H and y Y.
          By definition of base,

          any       y  H  T  B   s.t. y B  H
                                  r           r
          from which any y H Y 
                              Y  B    s.t. y Y B  G
                                      r   1          r
          i.e. any  y  G   Y B   B
                                      r   1
          s.t. y Y B  G.
                     r
          Thus it follows that   is a countable base for the topology  and Y. Consequently, (Y,  ) is
                            1
          second countable.
          Theorem 7: A second countable space is always separable.
          Proof: Let (X, T) be a second countable space.

          To prove: (X, T) is separable.
          Since X is second countable and hence a countable base  for the topology T on X. Members of
           may be enumerated as B , B , B , ...  .
                               1  2  3
          Choose an element x  from each B  and take A as the collection of all these x s.
                           i         i                                 i
          That is to say,  x  B     i  N                                      ...(1)
                             c
                          i
                                 
                           
          and            A {x : i N}                                               ...(2)
                              i
          Evidently      N ~ A  under the map i x
                                                i
          Therefore,     A is enumerable.



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