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Unit 31: Baire Spaces




          exist no subsets of Z  having empty interior, except for the empty set. Therefore Z  satisfies the  Notes
                          +                                                 +
          Baire condition vacuously.
          Lemma 1: X is a Baire space iff gives any countable collection { } of open sets in X, each of which
                                                            n
          is dense in X their intersection   is also dense in X.
                                      n
          Proof: Recall that a set  is dense in X if  C = X. The theorem now follows at once from the two
          remarks.
          1.   A is closed in X iff X-A is open in X.
          2.   B has empty interior in X if and only if X-B is dense in X.
          Lemma 2: Any open subspace Y of a Baire space X is itself a Baire space.

          Proof: Let A  be a countable collection of closed set of Y that have empty interiors in Y. We show
                    n
          that A  has empty interior in Y.
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          Let  A be the closure of A  in X; then  A  Y = A . The set  A has empty interior in X. For it
               n               n          n       n         n
          is a  non empty open set of X  contained in  A , then    must intersect A . Then     Y is a
                                                n
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          non-empty open set of Y contained in A , contrary to hypothesis.
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          If the union of the sets A  contains the non empty open set W of Y, then the union of the sets
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          A also contains the set W, which is open in X because Y is open in X. But each set  A has empty
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                                                                             n
          interior in X, contradicting the fact that X is a Baire space.
          31.1.2 Baire’s Category Theory
          Let (X, d) be a metric space and AX. The set A is called of the first category if it can be expressed
          as a countable union of non dense sets. The set A is called of the second category if it is not of the
          first category.
          Definition: A metric space is said to be totally of second category if every non empty closed
          subset of X is of the second category.


                 Example 2: Let q be arbitrary.

                           {q} = {q}  D ({q}),              [   A = A  D(A) ]
                              = {q}   = {q}
                        int {q} = int {q}
                              =  {G   : G is open, G  {q}} = .
          For every subset of  contains rational as well irrational numbers.
          Thus,          int {q} = .

          This proves that {q} is a non-dense subset of .
                             =  {{q} : a  }.
          Furthermore  is enumerable.
            is an enumerable union of non-dense sets.
          From what has been done it follows that  is of the first category.


                 Example 3: Consider a sequence <f (x)> of continuous functions defined from I = [0, 1]
                                             n
          into  s.t. f (x) = x   x  N.
                   n     n


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