Page 95 - DMTH503_TOPOLOGY
P. 95
Unit 9: The Metric Topology
Theorem 4: In any metric space, any closed sphere is a closed set. Notes
Proof: Let S 0 r [x ] denote a closed sphere in a metric space (X, d).
0
To prove that S 0 r [x ] is a closed set.
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For this we must show that S 0 r [x ] is open in X.
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Let x S 0 r [x ] be arbitrary,
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x S 0 r [x ] x S 0 r [x ]
0
0
d (x, x ) > r , S y X :d(y,x ) r 0 0
0 0 0 r [x ]
0
d (x, x ) – r > 0
0 0
r > 0, on taking r = d (x, x ) – r ...(1)
0 0
We claim S r(x) S 0 r [x ] .
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Let y S be arbitrary, so that, d (y, x) < r.
r (x)
d (x, x ) d (x, y) + d (y, x ).
0 0
d (y, x ) d (x, x ) – d (x, y) > d (x, x ) – r = r [on using (1)]
0 0 0 0
d (y, x ) > r y S
0 0 0 r [x ]
0
Thus, any y S y S 0 r [x ]
r (x) 0
S r(x) S 0 r [x ] 0
Given any x S , r 0 s.t. S S
0 r [x ] r(x) 0 r [x ] 0
0
This prove that S 0 r [x ] is open in x.
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Example 3: Give an example to show that the union of an infinite collection of closed sets
in a metric space is not necessarily closed.
Solution: Let 1 , 1 : n N be the infinite collection for the usual metric space (, d).
n
Now each member of this collection is a closed set, being a closed interval.
But 1 , 1 : n N 1 1 , 1 1 3 , 1 0,1 .
n 2
Since ]0, 1] is not closed, it follows that the union of an infinite collection of closed sets is not
closed.
Example 4: Show that every closed interval is a closed set for the usual metric on .
Solution: Let x, y where x < y. We shall show that [x, y] is closed.
Now – [x, y] = {a : a < x or a > y}
= {a : a < x} {a : a > y}
= ]–, x [] y, [
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