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Differential and Integral Equation




                    Notes          In other words, the Wronskian of two linearly dependent functions is identically zero on (a, b).
                                   The contrapositive of this result is that if W   0 on (a, b), then u  and u  are linearly independent
                                                                                     1    2
                                   on (a, b).


                                                                    2
                                                                               3
                                          Example 1: The functions u (x) = x  and u (x) = x  are linearly independent on the interval
                                                              1          2
                                                                           3
                                                                   2
                                   ( 1, 1). To see this, note that, since u (x) = x , u (x) = x , u  ( ) 2 ,  and u  ( ) 3x 2  ,  the Wronskian
                                                                                            x
                                                                               x
                                                                                    x
                                                              1       2       1            2
                                   of these two functions is
                                                                 x 2  x 3
                                                             W            3x  4  2x 4  x 4
                                                                 2x  3x  2
                                                                          2
                                                                               3
                                   This quantity is not identically zero, and hence x  and x  are linearly independent on ( 1, 1)
                                          Example 2: The functions u (x) = f(x) and u (x) = kf(x), with k a constant, are linearly
                                                                1            2
                                   dependent on any interval, since their Wronskian is
                                                                       f  kf
                                                                   W          0
                                                                       f  '  kf  '
                                   If the functions u  and u  are solutions of (2), we can show by differentiating  W  u u  u u
                                                 1    2                                                1 2  1 2
                                   directly that

                                                                  dW
                                                                         x
                                                                       a 1 ( )W  0.
                                                                   dx
                                   This first order differential equation has solution
                                                                             x
                                                                                t
                                                            W ( ) W (x 0 )exp  a 1 ( )dt                   ...(7)
                                                              x
                                                                             0 x
                                   which is known as Abel’s formula. This gives us an easy way of finding the Wronskian of the
                                   solutions of any second order differential equation without having to construct the solutions
                                   themselves.

                                          Example 3: Consider the equation

                                                                   1        1
                                                                y    y   1    y  0
                                                                   x       x  2
                                   Using Abel’s formula, this has Wronskian

                                                                         x  dt  x W (x  )  A
                                                        W ( ) W (x 0 )exp       0   0
                                                           x
                                                                          0 x t   x     x
                                   for some constant A.
                                   We end this section with a useful theorem.
                                   Theorem. If  u  and  u  are linearly independent solutions of the homogeneous, non-singular
                                              1     2
                                   ordinary differential equation (2), then the Wronskian is either strictly positive or strictly negative.
                                   Proof: From  Abel’s formula, and  since the  exponential function  does not change sign,  the
                                   Wronskian is identically positive,  identically negative  or identically  zero. We just need  to




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