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Differential and Integral Equation




                    Notes          Therefore for each value of n, we have a solution of (i) of the type
                                                    n    n 2 2 2  /L 2
                                                            c t
                                        V  , x t  A n  cos  xe
                                                    L
                                   Hence the complete solution of (i) is
                                                         n     2 2 2  2
                                        V  , x t  ' B  A n  cos  xe  n  c t  /L                         ...(xxvii)
                                                  n  1    L
                                   Using the initial condition (xxvi), we have

                                                               n x
                                        V x ,0  f x  ' B  A  cos  dx
                                                           n                                            ...(xxviii)
                                                       n  1     L
                                   If we integrate both sides w.r.t. x between the limits 0 to L, we have
                                             L
                                           1
                                         ' B  f x dx                                                     ...(xxix)
                                           L
                                             0
                                                                          n x
                                   Also if we multiply both sides of (xxviii) by cos   and then integrate w.r.t.  x between 0 to
                                                                           L
                                   L, we have
                                             L
                                            2        n x
                                        A      f x  cos  dx
                                         n                                                                ...(xxx)
                                            L         L
                                             0
                                   B, can also be written in a better way as
                                             L
                                           1
                                         ' B  f x dx
                                           L
                                             0
                                             L
                                         1 2         x
                                           .  f x  cos  0dx
                                         2 L         L
                                             0
                                         1
                                           A 0
                                         2
                                   Hence complete solution of (i) to be given by
                                               1           n x  n r c t /L
                                                                 2 2 2
                                        V  , x t  A 0  A n  cos  e                                       ...(xxxi)
                                               2            L
                                                    n  1
                                              L
                                            2        n x
                                   where A n   f x  cos  dx                                             ...(xxxii)
                                            L         L
                                              0
                                   Self Assessment

                                   3.  The heat equation is given by

                                           2 u   u
                                        K
                                           x  2  t



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