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Differential and Integral Equation




                    Notes          is non-zero. So there is one and only one solution of the system of n simultaneous equations  ,
                                                                                                              1
                                    , ... . Thus if D( )   0, then the system (7) has one and only one solution given by Gamer’s rule
                                   2   n
                                   i.e.
                                               1
                                                                                  n
                                                                   nk n
                                                    1k
                                                          2k
                                           k       D b 1  D b 2  ... D b  (k  1, 2, 3, ... )
                                              D ( )
                                   where D  denotes co-factor of (h, k) the elements of the determinant (8), correspondingly, the
                                          hk
                                   solution (1) has the unique solution
                                                      n
                                          y ( )  f  ( )  k  1  D b 1  D b 2  ... D b g k ( )               ...(9)
                                                                                x
                                                 x
                                            x
                                                                 2k
                                                                          nk n
                                                           1k
                                                     D ( )
                                   As D( )   0, the corresponding Fredholm equation of the first kind
                                                 1
                                                    x
                                                         u
                                                      u
                                          y ( )   K ( , ) ( )du                                           ...(10)
                                                        y
                                            x
                                                 0
                                   has only the trivial solution y(x)   0 as D( )   0.
                                   31.2 Resolvent Kernel H(x, u,  )
                                   If we now substitute the expression of b  in (5), the solution (9) can also be written as
                                                                   i
                                                          1
                                                                                            u
                                                 x
                                          y ( )  f  ( )    D h 1 ( )  D h 2 ( )  D h 3 ( ) ... D h  ( ) ( ) ( )du
                                                                                                u
                                                                                                  g
                                                                        u
                                                                                                    x
                                                                                 u
                                                                                               f
                                            x
                                                                u
                                                                     2k
                                                                                         nk n
                                                                             3k
                                                                                                   k
                                                            1k
                                                     D ( )  0
                                   but the sum under the integral sign can be considered as  the expansion of the negative of a
                                   determinant of the (n + 1) order i.e.
                                                 u
                                                         u
                                                                                g
                                            (D h 1 ( )  D h  2 ( )  D h  3 (4) ......  D b  ( ) ( )
                                                                              u
                                                                                  x
                                              ik
                                                                                 k
                                                                           nk n
                                                      2k
                                                              3k
                                                                          x
                                                          g
                                                             x
                                                                        g
                                                     0 g  ( ) ( ) ..................... ( )
                                                         x
                                                       1   2             n
                                                     h 1 ( ) 1  a 11  a 12 ......... a 1n
                                                       u
                                          =  ( , , )D x u   ......................................  a 2n  ...(11)
                                                     .................................................
                                                     h  ( )         (1   a  )
                                                       u
                                                      n                   nn
                                   Hence we can write equation (9) as
                                                          1
                                                                  f
                                                                    u
                                          y ( )  f  ( )    D ( , , ) ( )du                                ...(12)
                                                             x
                                                 x
                                                              u
                                            x
                                                     D ( )  0
                                   Defining the resolvent Kernel H(x, u,  ) by
                                                        u
                                                    D ( , , )
                                                      x
                                              u
                                            x
                                          H ( , , )                                                       ...(13)
                                                      D ( )
                                   so equation (12) becomes
                                                       1
                                                 x
                                          y ( )  f  ( )  H ( , , ) ( )du                                  ...(14)
                                            x
                                                                 u
                                                            u
                                                               f
                                                          x
                                                      0
                                   In the equation (13) the resolvent Kernel H(x, u,  ) is the quotient of two polynomials of the nth
                                   degree in   and the denominator is independent of x and u and this has important consequences.
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