Page 59 - DMTH504_DIFFERENTIAL_AND_INTEGRAL_EQUATION
P. 59

Differential and Integral Equation




                    Notes          where
                                                                           1
                                                                    2r  1
                                                              C =           f  ( ) ( )dx
                                                                             x
                                                                                 x
                                                                               P
                                                               r                r
                                                                      2
                                                                           1
                                                                         1
                                                                   (2r  1)
                                                                            P
                                                              C =         1. ( )dx    for  r  1, 2,...    ...(iii)
                                                                              x
                                                                             r
                                                               r      2
                                                                         0
                                   Putting  r  0, 1, 2, 3, ....
                                                                     1         1        1
                                                                    1         1       1    1
                                                                        x
                                                              C  =    P  ( )dx  1.dx   x
                                                               0    2  0      2       2    2
                                                                     0         0        0
                                                                     1         1        2  1
                                                                    3         3      3 x    3
                                                              C  =    P  ( )dx  xdx   .
                                                                        x
                                                               1       1
                                                                    2         2      2 2    4
                                                                     0         0         0
                                                                     1
                                                                    5
                                                              C  =    P 2 ( ) dx
                                                                        x
                                                               2    2
                                                                     0
                                                                     1
                                                                    5 1
                                                                 =     (3x 2  1)dx
                                                                    2 2
                                                                     0
                                                                             1
                                                                    5 3x  3
                                                                 =         x   0
                                                                    4  3
                                                                             0
                                                                     1
                                                                   7
                                                              C  =    P  ( )dx
                                                                        x
                                                               3    2  3
                                                                     0
                                                                     1
                                                                   7 1
                                                                             x
                                                                 =     (5x  3  3 )dx
                                                                    2 2
                                                                     0
                                                                   7 5x 4  3x 2  1
                                                                 =
                                                                    4  4   2
                                                                              0
                                                                   7 5   3
                                                                 =
                                                                    4 4  2
                                                                   7 5 6     7
                                                                 =
                                                                    4  4     6
                                                                    1     3       7
                                                             x
                                   So                       f ( ) =  P 0 ( )  P 1 ( )  P 3 ( ) ...
                                                                                      x
                                                                       x
                                                                              x
                                                                    2     4      16


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