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Measure Theory and Functional Analysis




                    Notes              For,                x  y   (x, y) = 0
                                                                  (x,y) 0

                                                                  (y, x) = 0
                                                                  y   x

                                   (b)  If x   y then every scalar multiple of x is orthogonal to y i.e. x   y    x   y for every scalar
                                           C.
                                       For, let   be any scalar, then

                                                         ( x, y) =  (x, y)
                                                               =  . 0
                                                               = 0
                                                           x   y   x   y.
                                   (c)  The zero vector is orthogonal to every vector. For every vector x in H, we have

                                                           (0, x) = 0
                                          0   x    for all x   H.
                                   (d)  The zero vector is the only vector which is orthogonal to itself. For,

                                                            2
                                       if x  x   (x, x) = 0     x   = 0   x = 0
                                       Hence, if x   x, then x must be a zero vector.

                                   24.1.2 Pythagorean Theorem

                                   Statement: If x and y are any two orthogonal vectors in a Hilbert space H, then
                                                             x + y   =   x – y   =   x   +   y  .
                                                                  2
                                                                               2
                                                                                     2
                                                                          2
                                   Proof: Given x   y   (x, y) = 0, then we must have
                                                   y   x i.e. (y, x) = 0
                                   Now                    x + y   2  = (x + y, x + y)
                                                               = (x, x) + (x, y) + (y, x) + (y, y)
                                                                    2
                                                               =   x   + 0 + 0 +   y   2
                                                                    2
                                                               =   x   +   y   2
                                   Also,                  x – y   2  = (x – y, x – y)
                                                               = (x, x) – (x, y) – (y, x) + (y, y)
                                                               =   x   – 0 – 0 –   y   2
                                                                    2
                                                               =   x   +   y   2
                                                                    2
                                                                       2
                                                                            2
                                                          x + y   2  =   x – y   =   x   +   y   2
                                   24.1.3 Orthogonal  Sets

                                   Definition: A vector x is to be orthogonal to a non-empty subset S of a Hilbert space H, denoted
                                   by x   S if x   y for every y in S.




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