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Measure Theory and Functional Analysis




                    Notes          or       |(z , y)|  {    y   – 2}   0                                   … (2)
                                                  2
                                                        2
                                              o
                                   The above result is true for all real   suppose that (z , y)   0. Then taking   positive and so small
                                                                            o
                                   that     y   < 2, we see from (2) that   |(z , y)|  {    y   – 2} < 0.
                                                                        2
                                           2
                                                                              2
                                                                    o
                                   This contradicts (2).
                                   Hence we must have (z , y ) = 0    z    y,   y   M.
                                                     o  o       o
                                          z    M.
                                           o
                                   This completes the proof of the theorem.
                                   24.2 Summary
                                      Let H be a Hilbert space. If x, y   H then x is said to be orthogonal to y, written as x   y, if
                                       (x, y) = 0.

                                      If x and y are any two orthogonal vectors in a Hilbert space H, then
                                                                       2
                                                                                  2
                                                                            2
                                                          x + y   2  =   x – y   =   x   +   y  .
                                      Two non-empty subsets S  and S  of a Hilbert space H are said to be orthogonal denoted by
                                                            1    2
                                       S    S , if x   y for every x   S  and every y   S .
                                        1   2                   1            2
                                      Let S be a non-empty  subsets of a Hilbert  space H. The orthogonal  compliment of  S,
                                       written as S  and is read as S perpendicular, is defined as
                                                              S  = {x  H : x  y   y  S}
                                      The orthogonal decomposition theorem: If M is a closed linear subspace of a Hilbert space
                                       H, then H = M   M .

                                   24.3 Keywords

                                   Orthogonal Compliment: Let S  be a non-empty subset of a Hilbert space H. The orthogonal
                                   compliment of S, written as S  and is read as S perpendicular, is defined as

                                                              S  = {x   H : x   y    y   S}
                                   Orthogonal Sets: A vector x is to be orthogonal to a non-empty subset S of a Hilbert space H,
                                   denoted by x   S if x   y for every y in S.
                                   Two non-empty subsets S  and S  of a Hilbert space H are said to be orthogonal denoted by S
                                                       1     2                                               1
                                   S , if x   y for every x   S  and every y   S .
                                    2                  1             2
                                   Orthogonal Vectors: Let H be a Hilbert space. If x, y   H then x is said to be orthogonal to y,
                                   written as x  y, if (x, y) = 0.
                                   Pythagorean Theorem: If x and y are any two orthogonal vectors in a Hilbert space H, then

                                                                          2
                                                                               2
                                                                                     2
                                                             x + y   =   x – y   =   x   +   y  .
                                                                  2
                                   24.4 Review Questions
                                   1.  If S is a non-empty subset of a Hilbert space, show that S  = S  .
                                   2.  If M is a linear subspace of a Hilbert space, show that M is closed    M = M .

                                   3.  If S is a non-empty subset of a Hilbert space H, show that the set of all linear combinations
                                       of vectors in S is dense in H    S  = {0}.



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