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Measure Theory and Functional Analysis




                    Notes
                                   Also by hypothesis, we have  N  N* =N* N  and N N*  N* N               … (2)
                                                            1   2   2  1    2  1    1  2
                                   we claim that N + N is normal.
                                                1   2

                                   i.e. (N + N )(N + N )* = (N + N )*(N + N )                              ...(3)
                                        1   2  1   2     1   2  1   2
                                   since adjoint operation preserves addition, we have

                                          (N + N )(N + N )* = (N + N ) N* +N*
                                            1   2  1   2     1   2   1   2
                                          N N*   N N   N N*   N N*                                         ...(4)
                                            1  1  1  2  2  1   2  2
                                          N N* 1  N* N 1  N* N 2  N* N 2
                                            1
                                                   2
                                                          1
                                                                2
                                   =       N*  N*   N  N
                                             1    2  1   2
                                   =       N   N * N   N       (using (1) and (2))
                                            1   2    1   2
                                           N  1  N  2  N 1  N *  N 1  N * N  1  N  2
                                                        2
                                                                  2
                                          N   N  is normal.
                                            1  2
                                   Now we show that N N is normal i.e.
                                                    1  2
                                           N N  N N *    N N * N N .
                                            1  2  1  2    1  2   1  2

                                     L.H.S.=  N N 2  N N *  N N N * N *  1
                                                  1
                                                    2
                                                               2
                                                            2
                                                          1
                                            1
                                                                      N N N * N *
                                                         1  2  2    1
                                                                      N N * N N *
                                                         1   2  2   1
                                                                       N N * 2  N N * 1
                                                          1
                                                                 2
                                                                       N * N  N * N
                                                           2  1   1  2
                                                                      N * N N * N
                                                          2  1   1  2
                                                                       N * N * 1  N N  2
                                                                  1
                                                           2
                                                                       N N * N N
                                                          1  2   1  2
                                           N N   N N *   N N * N N
                                            1  2  1  2    1  2   1  2
                                          N N is normal.
                                           1  2
                                   This completes the proof of the theorem.

                                   Theorem 4: An operator T on a Hilbert space H is normal   T * x  Tx  for every  x H.

                                   Proof: We have T is normal   TT* T * T
                                     TT * T * T  0




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