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Measure Theory and Functional Analysis




                    Notes          that  (T)   . Further, this equation in  has exactly n roots in complex field. If the equation has
                                   repeated roots, then the number of distinct roots are less than n. So that T has an eigenvalue and
                                   the number of distinct eigenvalue of T is less than or equal to n. Hence the number of elements
                                   of  (T) is less than or equal to n. This completes the proof of the theorem.


                                          Example: For a two dimensional Hilbert space H, let B = {e , e } be a basis and T be an
                                                                                         1  2
                                   operator on H given by the matrix

                                                             A =   11  12                                  … (1)
                                                                   21  22
                                   (i)  If T is given by Te  = e  and Te  = – e , find the spectrum T.
                                                      1  2      2    2
                                   (ii)  If T is an arbitrary operator on H with the same matrix representation, then
                                                          2
                                                         T  (   +   ) T + (      –      ) I = 0
                                                             11   22     11  22  12  21
                                   Sol:
                                   (i)  Using the matrix A of the operator T, we have

                                       Te  =    e  +    e  = e  so that    = 0 and    = 1
                                         1   11  1  21  2  2     11        21
                                       Te  =    e  +    e  = –e  so that    = –1 and    = 0
                                         2   12  1  22  2  1      12        22
                                                           0  1
                                       Hence [T] =   11  12     .
                                                    21  22  1 0
                                       For this matrix, the eigenvalue are given by the characteristic equation

                                                            1
                                                         1     = 0

                                             2  + 1 = 0   =  i so  (T) = {  i}.
                                   (ii)  Let us consider the eigenvalues of A, which are given by


                                                   11     12   = 0
                                                   21    22
                                             2  – (   +   )   + (      –      ) = 0                        … (2)
                                                 11   22     11  22  12  21
                                       Since (2) is true for  , we can take
                                                              T =  I                                       … (3)
                                       From (2) and (3) we get
                                             2
                                            T  – (   +   ) T + (      –      ) I = 0                       … (4)
                                                 11   22     11  22  12  21
                                       The operator T on H having   as an eigenvalue satisfies equation (4).
                                   Theorem 2: If T is an operator on a finite dimension Hilbert space, then the following statements
                                   are true.
                                   (a)  T is singular    0   (T)

                                                                             –1
                                   (b)  If T is non-singular, then   (T)  –1    (T )
                                                                  –1
                                   (c)  If A is non-singular, then  (ATA ) =  (T)
                                   (d)  If    (T) and if P is polynomial then P ( )   (P (T)).



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