Page 208 - DSOC404_METHODOLOGY_OF_SOCIAL_RESEARCH_ENGLISH

Methodology of Social Research

note Because the element 1100.5 is associated with the 1.560 element (because above that there is 1010 that
is smaller than 1100.5), therefore the wage associated with 1560 element is 30 i.e. the median will be
th
30 dollars. therefore, the median of wages=30 dollars.

Median of continuous series
n n + 1
Firstly we find the place of median using the formula instead of in a continuous series. the
2 2
class-interval in which the median is located is known as median class-interval. The formula to find
out the median in a continuous series is –
n − F
Me = L + 2 i ×
f
Where Me = Median
L = Lower limit of median class-interval
n = sum of frequencies
f = frequency of median class-interval
F = the cumulative frequency of previous median class-interval
t = the difference between the upper and lower limits of median
class-interval

Example 10 find the median in the table written below.

income (in `) No. of people
100–200 15
200–300 33

300–400 63
400–500 83
500–600 100

solution: To find the median we need to find out the cumulative frequency firstly to find out the
median as shown in the table given below-

income (in `) No. of people cumulative frequency
100–200 15 15
200–300 33 (15 + 33) = 48
300–400 63 (48 + 63) = 111
400–500 83 (111 + 83) = 194
500–600 100 (194 + 100) = 294
n = 294

202 loVely professional uniVersity