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Quantitative Techniques – I
Notes 5
This condition gives p
24
Further
1 5 1 5 1
E ( ) 2. 1. 0. 1. 2. 0
X
6 24 4 24 6
2 1 5 1 5 1 7
E (X ) 4. 1. 0. 1. 4.
6 24 4 24 6 4
X
E (X 2) E ( ) 2 0 2 2
And (2E X 2 3X 5) 2 (X 2 ) 3 ( ) 5 2. 7 0 5 8.5
E
E
X
4
Self Assessment
Fill in the blanks:
9. Expected value of a constant is the ...................................
10. When a random variable is expressed in monetary units, its expected value is often termed
as ...............................
11. If X and Y are two random variables, then E(X + Y) = ......................................
12.3 Counting Techniques
Counting techniques or combinatorial methods are often helpful in the enumeration of total
number of outcomes of a random experiment and the number of cases favourable to the
occurrence of an event.
12.3.1 Fundamental Principle of Counting
If the first operation can be performed in any one of the m ways and then a second operation can
be performed in any one of the n ways, then both can be performed together in any one of the
m × n ways.
This rule can be generalised. If first operation can be performed in any one of the n ways, second
1
operation in any one of the n ways, ...... kth operation in any one of the n ways, then together
2 k
these can be performed in any one of the n × n × ...... × n ways.
1 2 k
12.3.2 Permutation
A permutation is an arrangement of a given set of objects in a definite order. Thus composition
and order both are important in a permutation.
1. Permutations of n objects: The total number of permutations of n distinct objects is n!.
Using symbols, we can write = n!, (where n denotes the permutations of n objects, all taken
together).
Let us assume there are n persons to be seated on n chairs. The first chair can be occupied
by any one of the n persons and hence, there are n ways in which it can be occupied.
Similarly, the second chair can be occupied in n – 1 ways and so on. Using the fundamental
principle of counting, the total number of ways in which n chairs can be occupied by
n persons or the permutations of n objects taking all at a time is given by:
n
P = n(n – 1)(n – 2) ...... 3.2.1 = n!
n
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