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Unit 14: Multivariate Analysis



                                                                                                  Notes
                                                Table

               Attribute                    1     2      3     4      5     6     7
               Brand – A                    1     0      0     1      0     0     1
               Brand – B                    0     0      1     1      1     0     0

            One measure of simple matching S is given by:

                                      
                                     a d
                             S =
                                  a b c d
                                   
                                        
                                      
            Where            a = No. of attributes possessed by brands A and B
                             b = No. of attributes possessed by brand A but not by brand B
                             c = No. of attributes possessed by brand B but not by brand A
                             d = No. of attributes not possessed by both brands.
                                     1 2     3
                                      
            Substituting, we get S =           0.43
                                   
                                  1 2 2 2    7
                                        
                                      
            A and B’s association is to be the extent of 43%.
            It is now clear that object A possess attributes 1, 4, and 7 while object B possess the attributes 3,
            4 and 5. A glance at the above table will indicate that objects A and B are similar in respect of 2
            (0 & 0), 6 (0 & 0) and 4 (1 & 1). In respect of other attributes, there is no similarity between A and
            B. Now we can arrive at a simple matching measure by (a) counting up the total number of
            matches – either 0, 0 or 1, (b) dividing this number by the total number of attributes.
            Symbolically  SAB = M / N
                   SAB = Similarity between A and B
                     M = Number of attributes held in common (0 or 1)
                     N = Total number of attributes
                   SAB = 3 / 7 = 0.43
            i.e., A & B are similar to the extent of 43%.

            Self Assessment

            Fill in the blanks:
            6.   In a  typical correspondence analysis, a  cross-tabulation  table of  frequencies is  first
                 .......................
            7.   ....................... Analysis is a technique used for classifying objects into groups.
            8.   The ....................... application of cluster analysis is in customer segmentation and estimation
                 of segment sizes.

            14.4 Conjoint Analysis

            Conjoint analysis is concerned with the measurement of the joint effect of two or more attributes
            that are important from the customers’ point of view. In a situation where the company would
            like to know the most desirable attributes or their combination for a new product or service, the
            use of conjoint analysis is most appropriate.






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