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Unit 7: Limits




           Step 3:  Put h = 0 and get the required result       =                               Notes

                                                              As x   0, h   0
                                                    Thus,       = 6 + 0 = 6

                                                    by putting h=0
          Consider the example:


          Find      , where f(x) =



          Here, for x   1, f(x) =



                         =



          It shows that if f(x) is of the form    , then we may be able to solve it by the method of factors .

          In such case, we follow the following steps:
           Step 1:  Factorise g(x) and h (x)
                                      Sol.   f(x) =


                                                =


                                      (Q x  1.   x–1   0 and as such can be cancelled)

           Step 2:  Simplify f(x)
                                             f(x) =

           Step 3:  Putting  the  value  of
                                                =
                 x,  we  get  the  required
                 limit
                                        Also f(1) = 1(given)
                                      In this case,

          Thus, the limit of a function f (x) as x   a may be different from the value of the function at
          x = a.
          Now, we take an example which  cannot be solved by the method of substitutions or method of
          factors.

          Evaluate

          Here, we do the following steps:

          Step 1: Rationalise the factor containing square root.
          Step 2: Simplify.




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