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Unit 13: Combinations




               In part a above, we observed all probable draws.  From that list we only want the ones  Notes
               that include 1 RED and 2 WHITE marbles.
               Let us observe  what the draw appears like:  we would have to have 1 red and 2 white
               marbles to fulfill this condition:
               1 RED    2 WHITE
               First we are required to find n and r:

               Jointly that would make up 1 draw.  We are going to have to utilize the counting principle
               to assist us with this one.
               Note how 1  draw is divided into two parts – red and white.   We can not unite them
               together since we require a specific number of each one. So we  will comprehend how
               many ways  to get 1 RED and how many ways  to get 2 WHITE, and by means of the
               counting principle, we will multiply these numbers together.
          1 RED:
          If n is the number of RED marbles we have to select from,  what do you think n is in this problem?

          If you said n = 3 you are right!!!  There are a total of  3 RED marbles.
          If r is the number of RED marbles we are drawing at a time, what do you think r is?
          If you said r = 1, pat yourself on the back!! 1 RED marble is drawn at a time.
          2 WHITE:

          If n is the number of WHITE marbles we have to choose from,  what do you think n is in this
          problem?
          If you said n = 5 you are right!!!  There are a total of 5 WHITE marbles.

          If r is the number of WHITE marbles we are drawing at a time, what do you think r is?
          If you said r = 2, tap yourself on the back!! 2 WHITE marbles are drawn at a time.
          Let us place those values into the combination formula and see what we obtain:


                                                      n
                                                           r
                                  ! n           *RED:   = 3,   = 3
                          C 
                          n  r
                                                             r
                              (n r )! !         *WHITE:   = 5,   = 2
                                                        n
                                    r
                                
                                   3!      5!
                          C  . C      .        *Eval. inside ( )
                          3  1 5  2
                                   
                                 ( 3 1 1! ( 5 2 2!
                                            )
                                             !
                                          
                                     )
                                     !
                            3!  5               *Expand 3! until it gets to 2!
                             .
                                !
                           2 1 3 2!             *Expand 5! until it gets to 3!
                            !
                             !
                                .
                             !
                            .
                           3 2 5 4 3!
                               .
                                               *Cancel out 2!'s and 3!'s
                           2 1 3 2!
                                !
                             !
                            !
                           3 5 4
                            . .
                           1 2 1
                            3 10
                            .
                            30
          If you contain a factorial key, you can put it in as 3!, times 5!, divided by 2!, divided by 1!, divided
          by 3!, divided by 2! and then press enter or =.
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