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Basic Mathematics – I




                    Notes              Cofactor of 2 = + (80   5) = 75
                                       Cofactor of 7 =   (32 + 3) =   35                                I column
                                       Cofactor of   3 = + (20 + 30) = 50
                                       Cofactor of 4 =   (56 + 15) =   71
                                       Cofactor of 10 = + (16   9) = 7                                 II column

                                       Cofactor of 1 =   (10 + 21) =   31
                                       Cofactor of   3 = + (7 + 30) = 37
                                       Cofactor of 5 =   (2 + 12) =   14                               III column
                                       Cofactor of 8 = + (20   28) =   8

                                                  75   71  37
                                         Adj A    35  7    14
                                                  50   31   8


                                          Example: Find the inverses of the following matrices provided they exist:

                                      1   1                 2 0                  1   1
                                   1.                   2.                    3.
                                      2  0                  4  1                 3  4

                                                            1  2   1              1   2  0
                                      5   2
                                   4.                   5.   1 2  1           6.   3  1  5
                                      3  7
                                                            1  1   1              4  7   1


                                      0   2  4             2   1  1
                                   7.   1  7  3         8.  1  2  0
                                      2   5   4            3   4   5

                                   Solution:

                                               1   1
                                   1.   Let A
                                               2  0

                                             1  1
                                       | |          0 2  2  0
                                        A
                                             2  0
                                       Cofactor of 1   = + (0) = 0

                                       Cofactor of   1 =   (2) =   2                                    I column
                                       Cofactor of 2   =   (  1) = 1
                                       Cofactor of 0   = + (1) = 1                                     II column

                                                  0  1
                                         Adj A
                                                  2 1






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