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Unit 6: Measures of Central Tendency




                                                                                                Notes
                 Example: Calculate weighted geometric mean of the following data:

                                 Variable   X  :  5  8 44 160 500
                                  Weights   w  : 10 9  3  2  1
          How does it differ from simple geometric mean?
          Solution:
                                 Calculation  of weighted  and simple  GM

                                              w
                                   X    Weights  ( )  log X  wlog X
                                      5    10     0.6990  6.9900
                                      8     9     0.9031  8.1278
                                    44      3     1.6435  4.9304
                                   160      2     2.2041  4.4082
                                   500      1     2.6990  2.6990
                                  Total    25     8.1487 27.1554
                                             27.1554
                         Weighted GM = antilog       = antilog 1.0862 = 12.20
                                               25
                                          8.1487
                        Simple GM = antilog      (n = 5) = antilog 1.6297 = 42.63
                                            5
          Note that the simple GM is greater than the weighted GM because the given system of weights
          assigns more importance to values having smaller magnitude.



             Did u know?  Simple GM is greater than the weighted  GM because the given system of
             weights assigns more importance to values having smaller magnitude.

          6.6.3 Geometric Mean of the Combined Group

          If G , G , ...... G  are the geometric means of k groups having n , n , ...... n  observations respectively,
             1  2    k                                    1  2   k
          the geometric mean G of the combined group consisting of n  + n  + ...... + n  observations is
                                                            1   2        k
          given by
                               n 1 logG 1  n 2  logG 2    n k  logG k  n i logG i
                    G = antilog                            antilog
                                      n  n     n                      n
                                      1   2       k                      i

                 Example: If the geometric means of two groups consisting of 10 and 25 observations are
          90.4 and 125.5 respectively, find the geometric mean of all the 35 observations combined into a
          single  group.
          Solution.

                                              n 1 logG 1  n 2 logG 2
                         Combined GM = antilog
                                                   n 1  n 2
                         Here n  = 10, G  = 90.4 and n  = 25, G  = 125.5
                              1      1         2      2






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