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Research Methodology




                    Notes          4.  ss between columns:
                                                          ´
                                                    ´
                                            ´
                                         é 16 16  12 12  8 8 ù
                                       =  ê     +      +     ú  -  108
                                         ë  4       4     4 û
                                   5.  ss between rows:
                                                    ´
                                                          ´
                                                                ´
                                            ´
                                         é 10 10  10 10  3 3  13 13 ù
                                       =  ê     +      +     +      ú  -  108
                                         ë  3       3     3      3  û
                                         é 100  100  9  169 ù
                                       =  ê  +    +  +   ú  -  108
                                         ë  3   3   3  3 û
                                       = [33.33 + 33.33 + 3 + 56.33] - 108
                                       = 126 - 108
                                       = 18 (after adjusting fraction)
                                   6.  ss residual:

                                       = Total ss - (ss between column + ss between rows)
                                       = 32 – (8 +18) = 6.
                                       Now we need to set up ANOVA table.


                                         Variation     SS       d.f       M.S    F ratio   5%        1%
                                           source
                                      Between         8     (c–1) = 2   8/2=4    4/1=4   F (2, 6)   F (2, 6)
                                      columns               (r–1) = 3                    = 5.14   = 10.92
                                      Between rows    18                18/3=6   6/1=6   F (3, 6)   F (3, 6)
                                                                                         = 4.76   = 9.78

                                      Residual        6     (c–1) x (r–1)   6/6=1
                                                            = 6




                                   From the ANOVA table, we find that differences related to varieties of  incentives and  gain
                                   sharing are insignificant at 5% level as the calculated F-ratio, i.e., 4 is less than table value of F,
                                   which is 5.14. However differences are significant for different levels of technology at 5% level
                                   as the observed F ratio is higher than table value of F. At 1% level, however, differences are
                                   insignificant.

                                   Self Assessment

                                   Fill in the blanks:
                                   11.  ............................. is used to test the equality of three or more sample means.

                                   12.  For using ANOVA Data should be ……………..in nature








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