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Unit 6: Measures of Central Tendency




          2.   Given that there are n observations, the median is given by:                     Notes
                                 n  1
               (a)    The size of    th observations, when n is odd.
                                  2
                                          n        n  1
               (b)    The mean of the sizes of   th and   th observations, when n is even.
                                           2        2


                 Example: Find median of the following observations:
                 20, 15, 25, 28, 18, 16, 30.
          Solution:
          Writing the observations in ascending order, we get 15, 16, 18, 20, 25, 28, 30.

                                                 7 1
          Since n = 7, i.e., odd, the median is the size of   th  i.e., 4th observation.
                                                  2

          Hence, median, denoted by Md = 20.
          Note: The same value of Md will be obtained by arranging the observations in descending order
          of magnitude.


                 Example: Find median of the data : 245, 230, 265, 236, 220, 250.
          Solution:

          Arranging these observations in ascending order of magnitude, we get
          220, 230, 236, 245, 250, 265. Here  n = 6, i.e., even.

                                                6              6
               Median will be arithmetic mean of the size of  th, i.e., 3rd and   1 th , i.e., 4th observations.
                                                2              2
                    236 245
          Hence M             240.5
                 d     2
          When ungrouped frequency distribution is given

          In this case, the data are already arranged in the order of magnitude. Here, cumulative frequency
          is computed and the median is determined in a manner similar to that of individual observations.


                 Example: Locate median of the following frequency distribution:
                              Variable (X)  : 10 11 12 13 14 15 16
                              Frequency (f ) :  8  15 25 20 12 10  5
          Solution:
                                  X   : 10 11 12 13 14 15 16
                                   f  :  8  15 25 20 12 10    5
                                 c. f . :  8  23 48 68 80 90 95
                                                        th
                                                   95 1
          Here N = 95, which is odd. Thus, median is size of    i.e., 48th observation. From the table
                                                     2
          48th observation is 12,     M  = 12.
                                 d



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