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                                                                                       fJekJh^6 L fBy/VB L ;kg/y

                                        –1
                                                          –1
                                                  2
                T[dkjoD 5H cbB f (x) = sin  (2x 1 − x ) dk sin x d/ ;kg/y fBy/VB^r[DKe gsk eo'.   B'N
                jZb L wzfBnk










                d[pkok




                T[d'A                                                                                    T[Zso


                                                                          dy   x 2  1 − y 6
                                                  (
                                                        3
                                             6
                T[dkjoD 6H i/eo  1  − x 6  + 1 − y =  ax 3  − y )  j't/, sK f;ZX eo'   =  H
                                                  3
                                                                          dx   y  2  1 − x  6
                jZb L wzfBnk x  = sin θ, y  = sin φ ns/  1 x−  6  +1 y 6  = ax −  y 3  )
                                     3
                             3
                                                           −
                                                                    3
                                                                  3
                                                                   (















                                                                                                        T[Zso



                                                                      2
                                         1                   dy      dy
                T[dkjoD 7H i/eo  y=             , T[d'A x = 0 s/    ns/    dk wkB gsk eo'.
                                       x
                                    1+ + x  2  + x  3        dx      dx 2
                               1
                                         ++
                                              2
                                                    1 −
                jZb L  y=            = (1 x x +  x 3  )
                                2
                          1 xx +   x 3
                           ++


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