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Statistical Methods in Economics


                   Notes                          Total Number of cases = 100

                                                                     90
                                                  Required Probability =    = 0.9
                                                                     100
                                  Example 7:  What is the probability of getting a number greater than 4 with an ordinary die ?
                                  Solution:  Number greater than 4 in a die are 5 and 6.
                                              ∴   Number of favourable cases = 2
                                             Total number of cases = 6

                                                                 2   1
                                             Required Probability =    =
                                                                 6   3
                                  Example 8:  Find the probability of drawing a face card in a single random draw from a well
                                             shuffled pack of 52 cards.
                                  Solution:  There are 52 cards in a pack of cards.
                                             Total number of cases = 52
                                             Number of favourable cases (face cards include the Jack, Queen and King in each) = 12

                                                                 12   3
                                             Required Probability =    =
                                                                 52   13
                                  Example 9:  A card is drawn from an ordinary pack of playing cards and a person bets that it is a
                                             spade or an ace. What are odds against his winning this bet ?
                                  Solution:  Total number of cases = 52
                                             Since there are 13 spades and 3 aces (one ace is also present in spades), Therefore the
                                             favourable cases = 13 + 3 = 16

                                                                           16    4
                                             The probability of winning the bet =    =
                                                                           52   13
                                                                            4    9
                                             The probability of losing the bet =  1 −   =
                                                                            13   13
                                                                              9  4
                                             Hence, odds against winning the bet =   :   = 9: 4
                                                                             13 13
                                  Example 10: A single letter is selected at random from the word ‘PROBABILITY’. What is the
                                             probability that it is a vowel ?
                                  Solution:  There are 11 letters in the word ‘PROBABILITY’ out of which 1 is be selected.
                                              ∴   Total No. of words = 11
                                             There are four vowels viz. O, A, I, I. Therefore favourable number of cases = 4

                                                                          4
                                             Hence, the required probability =
                                                                         11
                                  Example 11: Find the probability of drawing an ace from a set of 52 cards.
                                  Solution:  Number of exhaustive cases (n) = 52
                                             There are 4 ace cards in an ordinary pack.
                                              ∴   Favourable cases (n) = 4
                                                                           4    1
                                              ∴   Probability of getting an ace =    =
                                                                          52   13





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