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Unit 26: Theory of Probability: Introduction and Uses


                                                                                                     Notes
                                          5  4  3  2  5   25
                                        =   ×× ××       =
                                          6  6  6  6  6  324
                       Probability of B’s winning in the 6th throw (6 or 5 or 4 or 3 or 2 or 1)
                                          5  4  3  2  1  6   5
                                        =   ×  ×  ×  ×  ×   =
                                          6  6  6  6  6  6  324

                                               1   5   25   169
                       A’s total chances of success =   +  +   =
                                               6  18  324   324
                                                5  5    5    155
                       B’s total chances of success =   +  +   =
                                               18  27  324   324
                       For a prize of Rs. 1,000
                                            169
                       A’s expectation = p × m =   × 1,000  = Rs. 521.6
                                            324

                                             155
                       B’s expectation =  p × m =   × 1,000  = Rs. 478.4
                                             324
            Example 17: A and B play for a prize of Rs. 99. The prize is to be won by a player who first throws
                       6 with one die. A first throws and if he fails B throws and if he fails A again throws
                       and so on. Find their respective expectations.

                                                               1
            Solution:  The probability of throwing 6 with a single die =
                                                               6
                                                                   1   5
                       The probability of not throwing 6 with single die =  −1   =
                                                                   6   6
                       If A is to win, he should throw 6 in the 1st, 3rd, or 5th...throws
                       If B is to win, he should throw 6 in the 2nd, 4th, 6th...throws
                       A’s chance of success in given by
                                                    4
                                                  5
                                          5
                                             1
                                                      1
                                       5
                                   1  ⎛ ⎞⎛⎞⎛⎞ ⎛⎞ ⎛⎞
                                                +
                                 =   +  ⎜ ⎟⎜⎟⎜⎟ ⎜⎟ ⎜⎟   +  ... ∞
                                       6
                                   6  ⎝ ⎠⎝⎠⎝⎠ ⎝⎠ ⎝⎠
                                             6
                                          6
                                                      6
                                                  6
                                               5
                                          5
                                   1  ⎡  ⎛⎞ 2  ⎛⎞ 4    ⎤
                                 =   ⋅  ⎢  +  ⎜⎟  +  ⎜⎟  +  ... ∞ ⎥1  [Infinite GP series: S =  ++1 aa 2  +... ∞ ]
                                   6  ⎢  ⎝⎠   ⎝⎠       ⎥ ⎣  ⎦
                                               6
                                          6
                                     ⎡       ⎤
                                   1  ⎢  ⎢  1  ⎥  ⎥  1  36  6  ⎛       1      First  Term  ⎞
                                 =   6 ⎢  ⋅  5  2  ⎥   =   6  ×  11   =   11  ⎜  ⎝  ∴S=  1  −  =  1 Common Ratio ⎟  ⎠
                                                                   ∞
                                                                            − a
                                         ⎛⎞
                                     ⎢  1 − ⎜⎟  ⎥
                                     ⎣   ⎝⎠ ⎦  6
                                             6
                       A’s expectation = p × m =   × 99  = Rs. 54
                                            11
                       B’s chance of success is given by
                                              3
                                                         1
                                   ⎛⎞⎛ ⎞ ⎛⎞ ⎛⎞ ⎛⎞     5  ⎛⎞
                                                     5
                                                1
                                            5
                                    5
                                       1
                                                  +
                                         +
                                 =  ⎜⎟⎜ ⎟ ⎜⎟ ⎜⎟ ⎜⎟      ⋅  ⎜⎟  +  ... ∞
                                                6
                                            6
                                    6
                                       6
                                                         6
                                                    6
                                   ⎝⎠⎝ ⎠ ⎝⎠ ⎝⎠ ⎝⎠       ⎝⎠
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