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bdkbZ—12% js[kh; izrhixeu fo'ys"k.k % ifjp; ,oa izrhixeu dh js[kk,¡




            mRiknu o o"kkZ osQ chp lglEcU/ xq.kkad                                                    uksV
             r = 0.5
            lEHkkfor mRiknu crkb, tcfd o"kkZ 9 lseh gksA
            gy (Solution):

            ekuk x = mit] y = o"kkZ
            Kkr gS %  x  = 10,  y  = 8, σ  = 8, σ  = 2, r = 0.5
                                 x     y
            x dk y ij izrhixeu lehdj.k (x on y)
                                                σ
                                         x −  x  =   x  y ( −  y)
                                                σ y
                                                  8
            Kkr eku j[kus ij]           x – 10 = .5 ×   (y – 8)
                                                  2
            ;k     x – 10 = 2(y – 8) ;k  x – 10 = 2y – 16  ;k  x = 2y – 6
            lEHkkfor mit tcfd o"kkZ 9 lseh gks]
                   x = 2 × 9 – 6 = 18 – 6 = 12 fdxzk izfr bdkbZ {ks=kiQy
            mnkgj.k (Illustration) 3: fuEu vkadM+ksa osQ vk/kj ij tks izrhixeu js[kk,a izkIr gksrh gSa muls (i) ifr dh
            izR;kf'kr vk;q Kkr djsa tc iRuh dh vk;q 12 o"kZ gS rFkk (ii) iRuh dh izR;kf'kr vk;q Kkr djsa tc ifr dh
            vk;q 33 o"kZ gSA
                                                          ekè;             izeki fopyu
                                                         (Mean)         (Standard deviation)
            ifr dh vk;q (Husband’s age)               25 o"kZ (years)       4 o"kZ (yeas)
            iRuh dh vk;q (Wife’s age)                 32 o"kZ (years)       5 o"kZ (years)

            ifr vkSj iRuh dh vk;q osQ chp lglEcU/ xq.kkad
                                                                       = 0.8
            gy (Solution):
            ekuk           x = ifr dh vk;q]  y = iRuh dh vk;q

            fn;k gqvk gS %  x  = 25, σ = 4, σ = 5, r = .8
            x dk y ij lehdj.k (x on y)          y dk x ij izrhixeu lehdj.k (y on x)
                             σ                                     σ
                     x =  x =  r  x  ( y −  y)              y =  y =  r  y  ( x −  x)
                             σ y                                   σ x
                           4                                      5
                x – 25 = 0.8 ×   (y – 22)              y – 22 = 0.8 ×   (x – 25)
                           5                                      4
            ;k   x – 25 = 0.64(y – 22)   ;k   ny – 22 = 1.0(x – 25)
            ;k       x = 0.64y + 14.08                     y = x – 25 + 22

            ;fn iRuh dh vk;q 12 o"kZ gks rks]  ;k          y = x – 3
            ifr dh vk;q x = 0.64 × 12 + 14.08 ;fn ifr dh vk;q 33 o"kZ gks] rks
                   = 7.68 + 14.08 = 21.76 o"kZ iRuh dh vk;q y = 33 – 3 = 30 o"kZ





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