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Unit 28: Sequences of Functions and Littlewood’s Third Principle




                                lim (B ) = 0.                                                  Notes
                                m®¥   m
          Choose N such that (B ) <  and let B = B . Then by definition of B , one can check that holds.
                             N              N                    N
          This concludes Step 1.
          Step 2: We now finish the proof. Let  > 0. Then by Step 1, for each k   we can find a measurable
          set A   X and a corresponding natural number N    such that
              k                                   k
                                                            1
                       (A ) <   and  for  x A  c  ,  |f(x) – f (x)| <   for all n > N .
                          k   k              k         n                 k
                             2                               k
          Now put A =  ¥ k 1 A . Then (A) <  and we claim that f  ® f uniformly on A . Indeed, let  > 0 and
                                                                     c
                          k
                       =
                                                     n
          choose k   such that 1/k < . Then
                                 ¥
                         x  A  =    A   x A  c k
                                   c
                                         
                             c
                                   j
                                 =
                                j 1
                                                    1
                                      |f(x) – f (x)| <    for all n > N
                                              n                 k
                                                    k
                                      |f(x) – f (x)| <  for all n > N .
                                              n                k
          Thus, f  ® f a.u.
                n
          We remark that one cannot drop the finiteness assumption.
          Self Assessment
          Fill in the blanks:
          1.   Let {f } be a sequence of ........................................... on a measure space (X,  S , ). We define
                   n
               the functions sup f , inf f , lim sup f , and lim inf f , by applying these limit operations
                              n    n         n           n
               pointwise to the sequence of extended real numbers {f (x)} at each point x  X.
                                                          n
          2.   If the sequence {f } is ................................, that is, either non-decreasing or non-increasing,
                             n
               then lim f  is everywhere defined and it is measurable.
                       n
                                                            p
          3.   If f and g are measurable, then .............................., and |f | where p > 0, are also measurable,
               whenever each expression is defined.
          4.   Every convergent series of measurable functions is ................................... when certain sets
               of measure  are neglected, where  can be as small as desired.

          28.4 Summary

              For a sequence {a } of extended real numbers, we know, in general, that lim a  does not
                             n                                                n
               exist; for example, it can oscillate. Assuming that the sequence continues the way it looks
               like it does, it is clear that although limit lim a  does not exist, the sequence does have an
                                                    n
               “upper” limiting value, given by the limit of the odd-indexed a ’s and a “lower” limiting
                                                                  n
               value, given by the limit of the even-indexed a ’s. Now how do we find the “upper” (also
                                                    n
               called “supremum”) and “lower” (also called “infimum”) limits of {a }? It turns out there
                                                                      n
               is a very simple way to do so, as we now explain.
              Let {f } be a sequence of extended-real valued functions on a measure space (X, S , ). We
                   n
               define the functions sup f , inf f , lim sup f , and lim inf f , by applying these limit operations
                                   n   n       n          n
               pointwise to the sequence of extended real numbers {f (x)} at each point x  X. For example,
                                                         n



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