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Unit 18: Theory of Space Curves




          Since the origins of the two frames coincide at the value t0, we have                 Notes
                                      x(t) – x(t) = x(t ) – x(t ) = 0
                                                 0
                                                      0
          for all t.
          This completes the proof  that two  families of  frames satisfying  the same  set of  differential
          equations differ at most by a single affine motion.

          Exercise 13: Prove that the equations  E (t) = q (t)E(t) can be written  E (t) = d(t) × E (t), where
                                                                    '
                                         '
                                                                    i
                                         i
                                                                              i
                                                    j
                                                ij
          d(t) = q (t)E (t) + q (t)E (t) + q (t)E (t). This vector is called the instantaneous axis of rotation.
                                   12
                                       3
                             2
                    1
                          31
                23
          Exercise 14: Under a rotation about the x -axis, a point describes a circle x(t) = (a cos(t), a sin(t), b).
                                          3
          Show  that its velocity vector satisfies x’(t) = d × x(t) where d = (0, 0, 1).  (Compare with the
          previous exercise.).
                                .
          Exercise 15: Prove that (v   v)(w·w)”(v·w)2 = 0 if and only if the vectors v and w are linearly
          dependent.
          18.5 Curves at a Non-inflexional Point and the Frenet Formulas
          A curve x is called non-inflectional if the curvature (t) is never zero. By our earlier calculations,
          this condition is equivalent to the requirement that x’(t) and x”(t) are linearly independent at
          every point x(t), i.e. x’(t) × x”(t)  0 for all t. For such a non-inflectional curve x, we may define a
          pair of natural unit normal vector fields along x.
                    x'(t)× x"(t)
          Let  b(t)  =       ,   called  the  binormal  vector  to  the curve  x(t).  Since  b(t)  is  always
                   |x'(t)× x"(t)|
          perpendicular to T(t), this gives a unit normal vector field along x.
          We may then take  the cross product of the vector fields b(t) and T(t) to obtain another unit
          normal vector field N(t) = b(t) × T(t), called the principal normal vector. The vector N(t) is a unit
          vector perpendicular  to T(t) and lying in the plane determined by x’(t) and x”(t).  Moreover,
          x”(t) · N(t) = k(t)s’(t) , a positive quantity.
                           2
          Note that if the parameter is arclength, then x’(s) = T(s) and x”(s) is already perpendicular to T(s).
                                                       x"(s)
          It follows that x”(s) = k(s)N(s) so we may define N(s) =    and then define b(s) = T(s) × N(s).
                                                       k(s)
          This is the standard procedure when it happens that the parametrization is by arclength. The
          method above works for an arbitrary parametrization.
          We then have  defined an  orthonormal frame  x(t)T(t)N(t)b(t)  called the  Frenet frame  of  the
          non-inflectional curve x.
          By the previous section, the derivatives of the vectors in the frame can be expressed in terms of
          the  frame  itself,  with  coefficients  that  form  an  antisymmetric  matrix.  We  already  have
          x’(t) = s’(t)T(t), so
                                     p (t) = s’(t), p (t) = 0 = p (t) .
                                      1
                                                        3
                                                2
          Also T’(t) = k(t)s’(t)N(t), so
                                    q (t) = k(t)s’(t) and q (t) = 0 .
                                     12
                                                     13
          We know that
                            b’(t) = q (t)T(t) + q (t)N(t), and q (t) = –q (t) = 0 .
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