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Unit 18: Theory of Space Curves




          From our earlier formulas, we have                                                    Notes
          x’(0) = s’(0)T(0),

          x”(0) = s”(0)T(0) + k(0)s’(0) N(0),
                               2
          x”’(0) = s”’(0)T(0) + s”(0)s’(0)k(0)N(0) + (k(0)s’(0) )’N(0) + k(0)s’(0) (–k(0)s’(0)T(0) + w(0)s’(0)b(0)).
                                                              2
                                                2
          Substituting these equations in the Taylor series expression, we find:
                          t 2    t 3                
                                                 3
                                            2
          x(t) = x(0) +  ts'(0)   s"(0)   ["'(0) k(0) s'(0) ] ... T(0)
                                        
                                                  
                    
                                                     
                          2      6                  
                     t   2  2  t 3                  2    
                                             
                                                       
                                                          
                     +    k(0)s'(0)   [s"(0)s'(0)k(0) (k(0)s'(0) ] ... N(0)
                      2        6                         
                     t   3      3   
                     +    k(0)w(0)s'(0)  ... b(0).
                                     
                      6             
          If the curve is parametrized by arclength, this representation is much simpler:
                          k(0) 2         k(0)  k'(0)          k(0)w(0)   
                                               2
                                                                          3
                                3
                                                       3
              x(s) =  x(0)    s   s   ... T(0)     s   s  ... N(0)    s  ... b(0).
                                    
                                                           
                                                                              
                            6             2     6               6        
          Relative to the Frenet frame, the plane with equation x  = 0 is the normal plane; the plane with
                                                      1
          x  = 0 is the rectifying plane, and the plane with x  = 0 is the osculating plane. These planes are
                                                  3
           2
          orthogonal respectively to the unit tangent vector, the principal normal vector, and the binormal
          vector of the curve.
          18.7 Plane Curves and a Theorem on Turning Tangents
          The general theory of curves developed above applies to plane curves. In the latter case there
          are, however, special features which will be important to bring out. We suppose our plane to be
          oriented. In the plane, a vector has two components and a frame consists of an origin and an
          ordered set of two mutually perpendicular unit vectors forming a right-handed system. To an
          oriented curve C defined by x(s) the Frenet frame at s consists of the origin x(s), the unit tangent
          vector T(s) and the unit normal vector N(s). Unlike the case of space curves, this Frenet frame is
          uniquely determined, under the assumption that both the plane and the curve are oriented.
          The Frenet formulas are
                                           x’ = T,

                                           T’ = kN,                                 (1)
                                          N’ = –kT .
          The curvature k(s) is defined with sign. It changes its sign when the orientation of the plane or
          the curve is reversed.
          The Frenet formulas in (1) can be written more explicitly. Let
                                       x(s) = (x (s), x (s))                       ...(2)
                                             1
                                                  2
          Then,
                                             '
                                                 '
                                      T(s) = (x (s),x (s)),
                                                 2
                                             1

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