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Abstract Algebra




                    Notes          Note that if f and g are disjoint, then fg=-gf, since f and g move disjoint sets of symbols.
                                   Now let us examine one more example. Let h be the permutation in S  defined by
                                                                                           5

                                       1 2 3 4 5
                                   h =   4 2 3 5 1  .
                                                 
                                   Following our previous rules, we obtain
                                   h = (1 4 5) (2) (3),
                                   because each of the symbols 2 and 3 is left unchanged by h. By convention, we don’t include the
                                   1-cycles (2) and (3) in the expression for h unless we wish to emphasize them, since they just
                                   represent the identity permutation. Thus, we simply write h = (1 4 5).
                                   The same process that we have just used is true for any cycle. That is, any r-cycle (i  i  . . . . . i ) can
                                                                                                           r
                                                                                                    1 2
                                   be written as (i  i ) (i  i ) . . . . . (i  i ), a product of transpositions.
                                                              2
                                                            1
                                                    1
                                                   1
                                                r
                                               1
                                   Now we will use Theorem 2 to state a result which shows why transpositions are so important
                                   in the theory of permutations.
                                   Theorem 2: Every permutation in S  (n  2) can be written as a product of transpositions.
                                                               n
                                   Proof: The proof is  really very simple. By Theorem 1 every permutation, apart from I, is  a
                                   product of disjoint cycles. Also, you have just seen that every cycle is a product of transpositions.
                                   Hence, every permutation, apart from I, is a product of transpositions.
                                   Also, I = (1 2) (1 2). Thus, I is also a product of transpositions. So, the theorem is proved.
                                   Let us see how Theorem 3 works in practice. This is the same as (1 4) (1 2) (1 3) (1 5).

                                                          1 2 3 4 5 6 
                                   Similarly, the permutation          
                                                          3 6 4 1 2 5  
                                   = (1 3 4) (2 6 5) = (1 4) (1 3) (2 5) (2 6).
                                   The decomposition given in Theorem 3 leads us to a subgroup of S  that we will now discuss.
                                                                                        n
                                   8.3 Alternating Group


                                   You have seen that a permutation in S  can be written as a product of transpositions. But all such
                                                                 n
                                   representations have one thing in common – if a permutation in S  is the product of an odd
                                                                                         n
                                   number of transpositions in one such representation, then it will be a product of an odd number
                                   of transpositions in any such representation. Similarly, if f  S  is a product of an even number
                                                                                    n
                                   of transpositions in one representation, then f is a product of an even number of transpositions
                                   in any such representation. To see this fact we need the concept of the signature or sign function.
                                   Definition: The signature of f  S , (n  2) is defined to be
                                                              n
                                            f(i) – f(i)
                                   sign  f  
                                         i,j 1  j – i
                                           
                                   For example, for f = (1 2 3)  S , 3

                                          f(2) – f(1) f(3) – f(1) f(3) – f(2)
                                   sign f =      .        .
                                           2 – 1    3 – 1   3 – 2







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