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Unit 3: Subgroups
Figure 3.1: 6th Roots of Unity Notes
Now, let = cos 2 isin 2 . Then all the nth roots of 1 are 1, , , ......., , since
n-1
2
n n
2 j 2 j
j
j
cos isin for 0 n 1 (using De Moivres theorem).
n n
Note is the Greek letter omega.
Example: Show that U (C, .).
n
Solution: Clearly, U, # 0. Now, let , U,.
1
j
Then, by the division algorithm, we can write i + j = qn + r for q, r Z, 0 r n 1. But then
i
r
n q
r
n
i+j
j
. = = qn+r = ( ) . = U,, since = 1. Thus, U, is closed under multiplication.
Finally, if U,, then 0 n i n 1 and . = = 1; i.e., is the inverse of o for all
ni
i
i
n-i
i
n
1 i < n. Hence, U is a subgroup of C*.
n
Note that U , is a finite group of order n and is a subgroup of an infinite group, C*. So, for every
n
natural number n we have a finite subgroup of order n of C*.
Before ending this we will introduce you to a subgroup that you will use off and on.
Definition: The centre of a group G, denoted by Z(G), is the set
z(G) = {G G | xg = gx x G}.
Thus, Z(G) is the set of those elements of G that commute with every element of G.
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