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Unit 3: Subgroups




          Now, let us see why <S>  A. We will show that A is a subgroup containing S. Then, by the  Notes
          definition of <S>, it will follow that <S>  A.
          Since any a  S can be written as a = a , S  A.
                                        1
          Since S  , A  .

          Now let x, y  A. Then x =  a a n 2  2  ..... a n k k
                                 n
                                  1
                                 1
          y =  b b .... b m r   a , b  S for 1  i  k, 1  j  r.
               m
                 m
                  2
                1
               1
                 2
                      r
                            j
                         j
          Then xy  = a a n 2 2  ..... a k n  k b b .... b m r   1
                                    m
                                 m
                     n
                 -1
                                  1
                      1
                                     2
                                 1
                                         r
                                    2
                     1
                      = a a n 2  2  ..... a n k k  b  1 m 1 .... b m 1  1   A.
                        1 n
                       1
          Thus, by Theorem 1, A is a subgroup of G. Thus, A is a subgroup of G containing S. And hence,
          <S>  A.
          This shows that <S> = A.
          Note that, if (G, +) is a group generated by S, then any element of G is of the form n  a  + n a  +
                                                                             1
                                                                                   2  2
                                                                               l
          ..... + n  a , where a , a ,....., a, S and n , n , ....., n ,  Z.
                         1
                           2
                                         1
                                           2
                                                 r
                 r
               r
          For example, Z is generated by the set of odd integers S = { ± 1, f3, ± 5, ......). Let us see why. Let
          m  Z. Then m = 2  where r  0 and s  S. Thus, m  <S>. And hence, <S> = Z.
                         r
                         s
          Definition: A group G is called a cyclic group if G = < {a) > for some a E G. We usually write
          < {a) > as < a >.
          Note that < a > = { a  | n "  Z ).
                          n
          A subgroup H of a group G is called a cyclic subgroup if it is a cyclic group. Thus, < (12) > is a
          cyclic subgroup of S  and 22 = <2> is a cyclic subgroup of Z.
                          3
          We would like to make the following remarks here.
          Remark: (i) If K  G and a  K, then < a >  K. This is because < a > is the smallest subgroup of
          G containing a.
          (ii) All the elements of < a > = { a  | n  Z) may or may not be distinct. For example, take
                                       n
          a = (12)  S .
                   3
          Then < (1 2) > = { I, (1 2)), since (1 2)  = I, (1 2)  = (1 2), and so on.
                                              3
                                       2
          We will now prove a nice property of cyclic groups.
          Theorem 7: Every cyclic group is abelian.
          Proof: Let G = < a > = { a  | n  Z). Then, for any x, y in G, there exist m, n  Z such that x = a , y
                             n
                                                                                    m
          = a . But, then, xy = a . a  a m+n  = a n+m  = a . a  = yx. Thus, xy = yx for all x, y in G.
                              n
                           m
             n
                                            m
                                          n
          That is G is abelian.
             Note    Theorem 7 says that every cyclic group is abelian. But this does not mean that
             every abelian group is cyclic.
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