Page 74 - DMTH403_ABSTRACT_ALGEBRA
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Unit 5: Normal Subgroups
For example, if G is a commutative group, then Notes
x y xy = x xy y = e x, y G. [G, G] = {e}.
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Theorem 6: Let G be a group. Then [G, G] is a normal subgroup of G. Further, G/[G, G] is
commutative.
Proof: We must show that, for any commutator x y xy and for any g G, g (x y- xy)g [G,G].
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Now g (x y- xy)g = (g xg) (g yg) (g xg) (g yg) [G, G].
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[G, G] G.
For the rest of the proof let us denote [G, G] by H, for convenience.
Now, for x, y G,
HxHY = H y Hx Hxy = Hyx (xy) (yx) H
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Thus, since xy x y H x, y G, HxHy = HyHx x, y G. That is, G/H is abelian.
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Note We have defined the quotient group G/H only if H G. But if H G we can
still define G/H to be the set of all left (or right) cosets of H in G. But, in this case G/H will
not be a group.
Remark: If H is a subgroup of G, then the product of cosets of H is defined only when H G.
This is because, if HxHy = Hxy x, y G, then, in particular,
Hx Hx = Hx x =He = H x G.
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Therefore, any h H, x hx = ex hx Hx Hx= H.
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That is, X Hx H for any x E G.
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H G.
Self Assessment
1. Every subgroup of a ................... group is a normal subgroup.
(a) associative (b) large
(c) cyclic (d) commutative
2. g Hg = ................... if h H where H is a subgroup of G.
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(a) g hg (b) gh g
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(c) gh g -1 (d) ghg
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3. The group of G is of order ................... is called dihedral group.
(a) 6 (b) 7
(c) 8 (d) 9
4. Every group of index ................... is normal.
(a) 4 (b) 5
(c) 3 (d) 2
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