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Statistics



                      Notes
                                           Example 49: An unbiased die is thrown 8 times. What is the probability of getting a six
                                    in at least one of the throws?
                                    Solution.

                                                                                                              1
                                                                                                        P A
                                    Let A  be the event that a six is obtained in the ith throw (i = 1, 2, ...... 8). Therefore,  ( ) 
                                         i                                                                 i   .
                                                                                                              6
                                    The event that a six is obtained in at least one of the throws is represented by (A   A    ....    A 8  ) .
                                                                                                  1
                                                                                                      2
                                    Thus, we have
                                          P (A   A    ....    A 8 ) 1 P A   (  1    A    ....    A 8 )
                                             1
                                                 2
                                                                      2
                                    Since A , A , ...... A  are independent, we can write
                                          1  2     8
                                                                                        8
                                                                                     æ
                                                                                      5ö
                                          P (A   A    ....    A  ) 1 P   ( ) ( ) . .... A  .P A  P  ( ) 1A   ç ÷  .
                                                                        2
                                                                               8
                                             1
                                                 2
                                                          8
                                                                   1
                                                                                     è  6 ø
                                           Example 50: Two students X and Y are very weak students of mathematics and their
                                    chances of solving a problem correctly are 0.11 and 0.14 respectively. If the probability of their
                                    making a common mistake is 0.081 and they get the same answer, what is the chance that their
                                    answer is correct?
                                    Solution.
                                    Let A be the event that both the students get a correct answer,  B be the event  that both get
                                    incorrect answer by making  a common mistake and  C be  the event  that both  get the  same
                                    answer. Thus, we have
                                          P (A C   )  P (  gets correct answer .X  ) (  gets correct answerP Y  )

                                                      ´
                                                            0.11 0.14   0.0154  (note that the two events are independent)
                                    Similarly,
                                     P (B C   )  P (  gets incorrect answerX  ) ´  P (  gets incorrect answerY  )


                                                                                   P (  and   make a common mistakeX  Y  )
                                                         ´
                                                       (1 0.11  )(1 0.14  ) 0.081 0.062´  
                                                                                    ) ,  since  A C b  g  and  B C b
                                                                 ( )
                                    Further,  C   (A C  ) (B C    )  or  P C   P (A C  ) P+  (B C    g   are
                                    mutually exclusive. Thus, we have

                                                P ( ) 0.0154 0.0620C   +    0.0774

                                    We have to find the probability that the answers of both the students are correct given that they
                                    are same, i.e.,

                                                        P (A  C )  0.0154
                                                      )
                                                P ( /A C               0.199
                                                          P C    0.0774
                                                           ( )




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