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Unit 7: Modern Approach to Probability



                                                                                                  Notes
                                   7  2   7  2  53
                          (A   ) B   +    ´  
                          P
                                   16  5  16  5  80
            Alternative Method :

                                      9  3  53
                              (A  B ) 1   ´  
                          P
                                     16  5  80
                   Example 38: If A and B are two events such that  P A B b  g  ,  find P(B),  P A B b  g ,
                                                                    1
                                                                    3
            P(A/B), P(B/A),  P A  d  Bi ,  P A  d  Bi  and P B d i. Also examine whether the events A and B are
            : (a) Equally likely, (b) Exhaustive, (c) Mutually exclusive, and (d) Independent.
            Solution.

            The probabilities of various events are obtained as follows:
            P B b g d  Bi b         1  +  1    1
                          +
                            P A Bg 
                 
                   P A
                                      6  3  2
                            b   2   1  1  5
                        P A Bg    +    
                                 3  2   3  6
                           / b   P A Bg    1  2  2
                                  b 
                        P A Bg    P B b g    3  ´  1    3
                                  b 
                           / b   P A Bg    1  3  1
                        P B Ag   P A b g    3  ´  2    2

                                 P Ai b
                        P A  d  Bi d  + P Bg d    Bi   1  +  1    1    2
                                             P A 
                                
                                            
                                                       3  2  6   3
                        P A  d  Bi    P A Bg    5    1
                                         b
                                 1
                                             1
                                                6   6
                                         1   1
                       P B d i =1- P B a f =1-  =
                                         2   2
            (a)  Since P(A)  P(B), A and B are not equally likely events.
                 Since  P A B b
            (b)             g  1, A and B are not exhaustive events.
                 Since  P A B b
            (c)             g  0 , A and B are not mutually exclusive.
                       b g
                              
            (d)  Since  P A P B b g b 
                                P A Bg , A and B are independent events.
                   Example 39: Two players A and B toss an  unbiased die   alternatively. He who first
            throws a six wins the game. If A begins, what is the probability that B wins the game?
            Solution.

            Let A  and  B  be the respective events that A and B throw a six in  i  th toss,  i  = 1, 2, .... .  B
                i     i
            will  win  the  game  if  any  one  of  the  following  mutually  exclusive  events  occur:
            A B    or  A B A B 2   or  A B A B A B 3  , etc.
                               1 1
                    1 1
             1 1
                                     3
                                    2
                                  2
                        2
                                             LOVELY PROFESSIONAL UNIVERSITY                                  103
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