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Unit 7: Modern Approach to Probability



            (c)  exactly two of them are able to solve the problem.                               Notes

            (d)  exactly one of them is able to solve the problem.
            Solution.
            Let A be the event that student A solves the problem. Similarly, we can define the events B and
            C. Further, A, B and C are given to be independent.
            (a)  The problem is solved if at least one of them is able to solve it. This probability is given by
                                                1  2  3  3
                 P (A    C ) 1 P   ( ) ( ) ( ) 1A  .P B  .P C    ´  ´  
                      B
                                                2  3  4  4
                 Here we have to find  P A B b   g b B C  g b A Cg
            (b)                                      
                                       ) 
                  P é ë (A  B ) (B   C ) (A   C ù û  P A P B  ( ) ( ) P A P C+  ( ) ( )
                                            ( ) ( ) P B P C+
                                                   ( ) ( ) ( )
                                                                                     2P A P B P C
                         1  1  1  1  1  1   1  1  1  7
                          ´  +  ´  +  ´    2. ´  ´  
                         2  3  3  4  2  4   2  3  4  24
                                                                   C d
                 The required probability is given by  P A B C  i d A B  i  B Ci
                                                 d
            (c)                                                        A   
                                                        ( ) ( ) ( )
                          ( ) ( ) B +
                                   ( ) ( ) P+
                                P A  .P  P B  .P C  ( ) ( ) 3A  .P C   P A  .P B  .P C
                         1  1  1  1  1
                                +  +      .
                        6  12  8  8  4
                 The required probability is given by  P A B d   C  i d  A  B C  i d A   B  Ci
                                                                  
            (d)
                                                      ( ) ( )
                          ( ) P B+
                                P A  ( ) P+  ( ) 2C   P ( ) ( ) 2A  .P B   P B  .P C
                                                   ( ) ( ) ( )
                                                            2P ( ) ( ) 3A  .P C +  P A  .P B  .P C
                         1  1  1  1  1  1  1  11
                                 +  +        +    .
                         2  3  4  3  6  4  8  24
            Note that the formulae used in (a), (b), (c) and (d) above are the modified forms of corollaries
            (following theorem 4) 3, 4, 5 and 6 respectively.


                   Example 32: A bag contains 2 red and 1 black ball and another bag contains 2 red and 2
            black balls. One ball is selected at random from each bag. Find the probability of drawing (a) at
            least a red ball, (b) a black ball from the second bag given that ball from the first is red; (c) show
            that the event of drawing a red ball from the first bag and the event of drawing a red ball from
            the second bag are independent.
            Solution.
            Let A  be the event of drawing a red ball from the first bag and A  be the event of drawing a red
                1                                               2
            ball from the second bag. Thus, we can write:
                          1 b                  1 d  2i
                                                        ´
                             A
                       n A  g   2 2   4,     n A   A   2 2   4,
                                   ´
                              2
                          1 d
                              2i
                                               1 d
                                                   2i
                       n A   A   1 2   2,      n A   A   1 2   2
                                   ´
                                                        ´
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