Page 51 - DMTH404_STATISTICS
P. 51
Unit 3: Conditional Probability and Independence Baye’s Theorem
Notice that the sum of the probabilities of the eight points in is Notes
which is as it should be.
Summarising the discussion so far, consider two random experiments and with sample
l 2
spaces S and S , respectively. Let u , u . . . be the points of S and let v , v . . ., be the points of S .
1 2 1 2 1 1 2 2
Suppose p , p , . . ,a nd q , q ,. . . are the associated probabilities, i.e., P(u ) = p and P(v) = q, with
1 2 l 2 i i j j
p , q 0 p 1, q 1. We say that and are independent experiments if the events “first
i j i j 1 2
i j
outcome is u ” and the event “second outcome is v ”, are independent,
i j
i.e., if the assignment of probabilities on the product space S1 x S2 is such that
P{(u, v)} = P(u ) P(v) = p q
j j i j i j
This assignment is a valid assignment because P((u , v)) 0 and
i j
P(u ,v ) = p q i
i
j
i
i j i j
= p i q 1.
j
i j
where the sums are taken over all values of i and j.
Can we extend these concepts to the case of n (n > 2) random experiments?
Let us denote the n random experiments by , , . . . , . Let S . S , . . . , S be the corresponding
1 2 n 1 2 n
sample spaces. Let P(x ) denote the probability assigned to the outcome x of the random
j j
experiment . We say that . . . , are independent experiments, if the assignment of probabilities
j 1 n
on the product space S × S × . . . × S is such that
1 2 n
P{(x , x , . . ., x )} = P(x ) P(x ) . . . P(x ).
1 2 n 1 2 n
The random experiments . . . , are said to be repeated independent trials of an experiment if
1 n
the sample space of ,. . . are all identical and so are the assignment of probabilities, it is in this
1 n
sense that the experiment discussed in Example 26 corresponds to 3 independent repetitions of
the experiment of inspecting a unit, where the probability of a unit being defective is P.
Before we conclude ow discussion of product spaces and repeated aials, let us revert to the case
of two independent experiments and with sample spaces S and S
1 2 1 2
Suppose
S = (u , u , . . . ), P(u ) = p , i 1
1 1 2 j i
S = (v , v ,... ), P(v) = q, j 1
2 1 2 j j
Let A = (u ,u ,....) and A = (v ,v ,...) be two events in S and S . Then A × A is event in
1 1 i 2 i 2 1 j 2 j 1 2 1 2
S × S and
1 2
A × A = {(u , v ) | r, s = 1, 2, . . .}.
1 2 r i s j
Under the assumption that E~ and E~ are independent, we can write
P(A1 × A2) = P{(u , v )}
s j
r i
r s
= p q j
i
LOVELY PROFESSIONAL UNIVERSITY 43