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Linear Algebra
Notes and so it must be that
T ' P 1 T . P ...(8)
This answers our questions.
Before stating this result formally, let us observe the following. There is a unique linear operator
U which carries onto ', defined by
U ' , j = 1,...,n
j j
This operator U is invertible since it carries a basis for V onto a basis for V. The matrix P (above)
is precisely the matrix of the operator U in the ordered basis . For, P is defined by
n
' P
j ij i
i 1
and since U ' , this equation can be written as
j j
n
U j P ij i .
i 1
So P = U , by definition.
Theorem 4: Let V be a finite-dimensional vector space over the field F, and let
B = = 1 ,..., n and ' = ' 1 ,..., ' n
be ordered basis for V. Suppose T is linear operator on V. If P = P 1 ,...,P n is the n×n matrix with
-1
columns P P T , then
j
T ' P 1 T . P
n
Alternatively, if U is the invertible operator on V defined by U ' , j 1,..., then
j j
T U 1 T U .
' '
Self Assessment
1. Let T be the linear transformation T R 3 R 3 , defined by
:
T (x,y,z) = (2y+z, x–4y, 3z)
find the matrix T, with respect to the basis
E 1,1,1 ,E 1,1,0 and E 1,0,0
1 2 3
2. A transformation T is defined by
1
T , x y = x –y x y
,
2
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