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Linear Algebra




                    Notes                 g  tf  f
                                           2   1  2
                                              2
                                          g 3  t f 1  2tf 2  f 3
                                              3
                                                   2
                                          g  4  t f  1  3t f 2  3tf 3  4 . f
                                   Since the matrix

                                              1 t t  2  t  3
                                              0 1 2 3t  2
                                                  t
                                          P
                                              0 0 1 3t
                                              0 0 0  1
                                   is easily seen to be invertible with

                                               1 t t  2  t  3
                                                     t
                                               0 1  2 3t 2
                                          P  1
                                               0 0  1   3t
                                               0 0  0  1
                                   it follows that   '  g 1 , g g g  is an  ordered  basis for  V. In Example 3, we  found that the
                                                        ,
                                                          ,
                                                            4
                                                         3
                                                       2
                                   matrix of D in the ordered basis   is
                                                0 1 0 0
                                                0 0 2 0
                                           D           .
                                               0 0 0 3
                                                0 0 0 0

                                   The matrix of D in the ordered basis  ' is thus

                                                   0  t t  2  t  3  0 1 0 0 1 t t  2  t 3
                                                         t
                                                   0 1  2 3t  2  0 0 2 0 0 1 2 3t t  2
                                   P  1  D P       0 0  1   3t  0 0 0 3 0 0 1 3t
                                        
                                                   0 0  0   1  0 0 0 0 0 0 0  1
                                                                    t
                                                    1  t t 2  t 3  0 1 2 3t 2
                                                          t
                                                    0 1  2 3t 2  0 0 2 6t
                                                    0 0  1  3t  0 0 0  3
                                                    0 0  0  1  0 0 0  0

                                                    0 1 0 0
                                                    0 0 2 0
                                                    0 0 0 3  .
                                                    0 0 0 0

                                                                                           
                                   Thus D is represented by the same matrix in the ordered basis   and  '. Of course, one can see
                                   this somewhat more directly since
                                          Dg   0
                                            1
                                          Dg 2  g 1



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