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Unit 12: Introduction and Characteristic Values of Elementary Canonical Forms




          Since c is a characteristic value of A if and only if det (A – cI) = 0, we form the matrix (xI – A) with  Notes
          polynomial entries,  and consider the polynomial  f = det (xI –  A). Clearly the characteristic
          values of  A in  F are just the scalars  c in  F such that f(c) = 0. For this reason  f  is called the
          characteristic polynomial of A. It is important to note that f is a monic polynomial which has
          degree exactly n. This is easily seen from the formula for the determinant of a matrix in terms of
          its entries.
          Lemma: Similar matrices have the same characteristic polynomial.

          Proof: If B = P  AP, then
                      –1
               det (xI – B) = det (xI – P PA)
                                   –1
                         = det (P (xI – A)P)
                                –1
                               –1
                         = det P . det (xI – A) . det P
                         = det (xI – A)
          This lemma enables us to define sensibly the characteristic polynomial of the operator T as the
          characteristic polynomial of any n × n matrix which represents T in some ordered basis for V.
          Just as for matrices, the characteristic values of T will be the roots of the characteristic polynomial
          for T. In particular, this shows us that T cannot have more than n distinct characteristic values. It
          is important to point out that T may not have any characteristic values.


                                                      2
                 Example 1: Let T be the linear operator on  R   which is represented in the standard
          ordered basis by the matrix
                                                0  1
                                           A =
                                                1  0
          The characteristic polynomial for T (or for A) is
                                                 x  1
                                    det (xI – A) =     = x  + 1.
                                                         2
                                                 1 x
          Since this polynomial has no real roots, T has no characteristic values. If U is the linear operator
              2
          on C  which is represented by A in the standard ordered basis, then  U has two characteristic
          value, i and –i. Here we see a subtle point. In discussing the characteristic values of a matrix A, we
          must be careful to stipulate the field involved. The matrix A above has no characteristic values
          in R, but has the two characteristic values, i and –i in C.

                 Example 2: Let A be the (real) 3 × 3 matrix

                                             3 1   1
                                             2 2   1
                                             2 2  0

          Then the characteristic polynomial for A is
                             x  3   1  1
                                                                   2
                               2  x  2 1   x 3  5x  2  8x  4 (x  1)(x  2) .
                               2    2  x
          Thus the characteristic values of A are 1 and 2.






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